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3 years ago

14

Tina works 15 hours a week (Monday to Friday). Last week she worked 3 ½ hours on Monday, 4 hours on Tuesday, 2 ⅙ hours on Wednes

day, and 1 ½ on Thursday. How many hours did she work on Friday?

1 answer:

algol133 years ago

6 0

She worked four hours and thirty minutes on friday

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Use the image below to answer the following question:

Nadya [2.5K]

Answer:

the ratios are both identical

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3 years ago

Enteroliths are calcifications that form in the gut of a horse. The stones can cause considerable morbidity and mortality. A stu

juin [17]

Answer:

A. mean=14.29

median=16

B. IQR=10

C. option 3

D. 5.91

Step-by-step explanation:

mean=sum of values/number of values=10+20+4+13+21+16+16/7=14.29

median is achieved by arranging data in increasing order and then calculating the middle value

4 10 13 16 16 20 21

The mid value is 16 so the median=16

IQR=interquartile range=3rd quartile-1st quartile=Q3-Q1=20-10=10

As n/4=7/4 is not an integer so

Q1=(n/4+1)value=(7/4+1)=2.75=2nd value=10

Q3=(3n/4+1)value=6.25=6th value=20

Standard deviation=s=sqrt(∑(x-xbar)²/n-1)=sqrt(209.43/6)=5.91

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3 years ago

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torisob [31]

Answer:

75.89

Step-by-step explanation:

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3 years ago

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Find the area of the triangle with the given vertices. Use the fact that the area of the triangle having u and v as adjacent sid

Gnom [1K]

Answer:

The area of the triangle is $A=\sqrt{\frac{4027}{2}}$

Step-by-step explanation:

Using the fact that the area of the triangle having u and v as adjacent sides is given by

$A=\frac{1}{2}||{\bf u} \times {\bf v} ||$

We know that we want to take a cross product to compute the area of the triangle, but we need to be careful because it doesn't make sense if we take the cross product of points.

The first step is to build some vectors that describe this triangle.

According with the graph we can build the vectors:

${\bf AB}$ and ${\bf AC}$

The vector ${\bf AB}$ is the difference of point B minus point A

${\bf AB}=(5-3,5-5,0-9)=(2,0,-9)$

and the vector ${\bf AC}$ is the difference of point C minus point A

${\bf AC}=(-4-3,0-5,2-9)=(-7,-5,-7)$

Next we need to find the cross product of this vectors.

${\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}$

This is the definition of cross product of two vectors in space:

Let ${\bf u} = u_1{\bf i}+u_2{\bf j}+u_3{\bf k}$ and ${\bf v} = v_1{\bf i}+v_2{\bf j}+v_3{\bf k}$ be vectors in space. The cross product of ${\bf u}$ and ${\bf v}$ is the vector

${\bf u} \times {\bf v}=(u_2v_3-u_3v_2){\bf i}-(u_1v_3-u_3v_1){\bf j}+(u_1v_2-u_2v_1){\bf k}$

Applying this definition we get

${\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}$

$\begin{pmatrix}0\cdot \left(-7\right)-\left(-9\left(-5\right)\right)&-9\left(-7\right)-2\left(-7\right)&2\left(-5\right)-0\cdot \left(-7\right)\end{pmatrix}\\\\\begin{pmatrix}-45&77&-10\end{pmatrix}$

$||{\bf AB} \times {\bf AC}||=\sqrt{(-45)^2+(77)^2+(-10)^2} \\\\||{\bf AB} \times {\bf AC}||=\sqrt{2025+5929+100}\\\\||{\bf AB} \times {\bf AC}||=\sqrt{8054}$

The area of the triangle is

$A=\frac{1}{2}||{\bf AB} \times {\bf AC} ||=\frac{1}{2}\sqrt{8054}=\sqrt{\frac{4027}{2}}$

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4 years ago

Do<br>main of ln(2x+3/×-1)

lozanna [386]

<span>so your equation would be 2x-3=-1 then your answer would be -1

</span>

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4 years ago