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Oliga [24]
3 years ago
7

PLEASE HELP ME REALLY QUICK

Mathematics
2 answers:
bulgar [2K]3 years ago
8 0

Answer:

41

Step-by-step explanation:

BDA = DBC+CBA

84=5x+3 + 6x-7

Combine like terms

84 = 11x-4

Add 4 to each side

84+4= 11x -4+4

88 =11x

Divide each side by 11

88/11 = 11x/11

8 = x

We want angle  ABC

ABC = 6x-7

       =6*8 -7

      =48-7

     =41

katovenus [111]3 years ago
5 0

Answer:

∠ABC   = 41°

∠ DBC  = 43°

Step-by-step explanation:

6x-7 + 5x+3 = 84

6x + 5x = 84 - 3 + 7

11x = 88

x = 8

∠ABC   = 6x-7

           = 6*8 - 7

           = 48 - 7

           = 41°

∠ DBC = 5x + 3

           = 5*8 + 3

           = 40 + 3

            = 43°

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Answer:

y = \frac{5}{6} x + \frac{8}{3}

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, 1) and (x₂, y₂ ) = (4, 6)

m = \frac{6-1}{4+2} = \frac{5}{6} , thus

y = \frac{5}{6} x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (4, 6 ), then

6 = \frac{20}{6} + c ⇒ c = 6 - \frac{20}{6} = \frac{16}{6} = \frac{8}{3}

y = \frac{5}{6} x + \frac{8}{3} ← equation of line

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Jesse has 5 and 3/4 dozen eggs. How many eggs does he have.
Leviafan [203]
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G 3.6 Dice rolls. If you roll a pair of fair dice, what is the probability of (a) getting a sum of 1
Paladinen [302]

Answer:

0

Step-by-step explanation:

In the roll of a pair of fair dice, The sample space is as follows:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

If x,y represent  the  possible outcome of rolling the two die

Then the total number of possibilities for  the sample space = (x,y)

= (6 × 6) = 36

Now, the probability of getting a sum of 1 does not exist in the roll of a pair of  fair dice.

Therefore, Probability(1) = 0

8 0
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