How to subtract this question 91.49-0.7

2 answers:

7 0

1. Line up the decimals
2. Subtract normally as if there were no decimals
3. Move the decimal directly down.
The answer is 90.79

Ilya [14]3 years ago

4 0

We can start by leaving the 9 in the hundreths place alone as this is not affected. We can then subtract 7 from 4 for the tenths place. This gives -3. As this is a negative number, we need to subtract 1 from the next place (the units) and then take another 3 from the tenths place. This gives us an answer of 90.79 (where both the 9's are unaffected).

You might be interested in

Which is bigger 5/8 or 7/12

gladu [14]

5/8=0.625

7/12=0.583......

5/8 is bigger as ive put both into a decimal as it is easier to tell

4 0

3 years ago

Read 2 more answers

Find the y-intercept of the line on the graph.<br>

Darya [45]

Answer:

The y-intercept is the place where the line meets the y-axis

Step-by-step explanation:

7 0

3 years ago

I'm confused for some reason can you help?

Nimfa-mama [501]

Answer:

So basically you just count how many squares you see. I see 21 squares so your answer would be 21 cubic units please mark me brainliest and have a wonderful day

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

How do you solve: 4/10y+28=0

Bezzdna [24]

Answer:

Step-by-step explanation:

$\dfrac{4}{10}y+28=0\qquad\text{subtract 28 from both sides}\\\\\dfrac{4:2}{10:2}y=-28\\\\\dfrac{2}{5}y=-28\qquad\text{multiply both sides by 5}\\\\5\!\!\!\!\diagup^1\cdot\dfrac{2}{5\!\!\!\!\diagup_1}y=-140\\\\2y=-140\qquad\text{divide both sides by 2}\\\\y=-70$

3 0

3 years ago

On a coordinate plane, a line is drawn from point C to point D. Point C is at (negative 1, 4) and point D is at (2, 0). Point C

skelet666 [1.2K]

Answer:

distance = 5 units

Step-by-step explanation:

In order to solve this problem we can start by plotting the two points you were provided with (see attached picture). This will help us visualize the problem better.

Now, we need to find the distance between those two points, so in order to do so we can use the distance formula:

$distance = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

in this case the x's and y's are given by the given points, since they are written as ordere pairs. And ordered pairs are written in the form (x,y). So for Point C:

C=(-1,4)

$x_{1}=-1$