On a blueprint with a scale of 1 cm = 4 ft, the length of the wall is 9 cm. If the scale of the blueprint were 1 cm = 3 ft, what
s would be the length of the wall?
1 answer:
Answer:
The length of the wall would be 12 cm
Step-by-step explanation:
step 1
we know that
On a blueprint with a scale of 1 cm = 4 ft, the length of the wall is 9 cm
so
The actual length of the wall is equal to ------> 9*4=36 ft
step 2
If the scale of the blueprint were 1 cm = 3 ft
then
The length of the wall in the new blueprint would be ----> 36/3=12 cm
You might be interested in
The Lagrangian,
has critical points where its partial derivatives vanish:
tells us 
, so that
Then with 
, we get
and 
tells us
Then there are two critical points, 
. The critical point with the negative 
-coordinates gives the maximum value, 
.
Answer:
312
Step-by-step explanation:
T.S.A : ( 2 × L × w ) + ( 2 × h × w ) + ( 2 × L × h ) = Area
9 - 3 = 6 - 3 = 3
( 2 × 12 × 3 ) + ( 2 × 8 × 3 ) + ( 2 × 12 × 8 ) = Area
72 + 48 + 192 = 312
N=80 the correct answer during
Answer:
can you give me choices?
Step-by-step explanation:
3,020
fghgfdfdsdfsdfdsdfdf
