3 years ago

Hi all i really need help this is multiple choice

Mathematics

2 answers:

Amanda [17]3 years ago

4 0

Supplementary angles

Simora [160]3 years ago

3 0

Supplementary angles

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The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in

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We have been given a quadratic function $f(x)=(x-5)^{2} +2$ and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is $[2,\infty)$ .

If we restrict the domain of this function to either $(-\infty,5]$ or $[5,\infty)$ , it will become one to one function.

Let us know find its inverse.

$y=(x-5)^{2}+2$

Upon interchanging x and y, we get:

$x=(y-5)^{2}+2$

Let us now solve this function for y.

$(y-5)^{2}=x-2\\
y-5=\pm \sqrt{x-2}\\
y=5\pm \sqrt{x-2}\\$

Hence, the inverse function would be $f^{-1}(x)=5+\sqrt{x-2}$ if we restrict the domain of original function to $[5,\infty)$ and the inverse function would be $f^{-1}(x)=5-\sqrt{x-2}$ if we restrict the domain to $(-\infty,5]$ .

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Solve for n.<br><br> 6 + 2n = 10<br><br> n =

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Step-by-step explanation:

<h2>Answer:-</h2>

$\tt{6+2n = 10}$

$\tt{2n = 10-6}$

$\tt{2n = 4}$

$\tt{n = \dfrac{4}{2}}$

$\boxed{\tt{n=2}}$

Hope it helps :)

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