How do i solve -2y=8

2 answers:

6 0

Divide each side of the equation by -2. (Or multiply each side by -1/2 ... same thing.) Then step quickly to one side, to avoid being struck as the solution jumps off of the paper at you.

Viefleur [7K]3 years ago

4 0

If you're trying to solve for y
-2y = 8
Divide -2 to both sides
$\frac{-2y}{-2} = \frac{8}{-2}$
Cancel out the -2 on the left, Divide the -2 to the 8 on the right so
y = -4

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$\text{The vertex form of a quadratic equation}\ f(x)=ax^2+bx+c:\\\\f(x)=a(x-h)^2+k\\\\(h,\ k)-\text{vertex}\\=====================================$

$\bold{METHOD\ 1:}\\\\\text{convert to the perfect square}\ (a+b)^2=a^2+2ab+b^2\qquad(*)\\\\f(x)=x^2+2x-3=\underbrace{x^2+2(x)(1)+1^2}_{(*)}-1^2-3\\\\f(x)=(x+1)^2-4\\==============================$

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