2 years ago

1 mi = 1.6 km How many miles are in 39.2 kilometers?

Mathematics

2 answers:

evablogger [386]2 years ago

6 0

Answer:

24.35775

Step-by-step explanation:

Ty for points xd

AleksandrR [38]2 years ago

5 0

Answer:

24.35 miles

Step-by-step explanation:

just divide 39.2 by 1.6

You might be interested in

. He has $75 in his checking account and has already spent $53.86 on food. Which inequality represents how much Jeremy has left

mixas84 [53]

X= 75-53.86
hope it helps!

4 0

3 years ago

a parking lot has total of 60 cars and trucks. the ratio of cars to trucks is 7:3 how many cars are in the parking lot. How many

Lerok [7]

7+3=10
60/10=6
6x7=42
6x3=18
there is 18 trucks in the parking lot

7 0

2 years ago

Suppose the population of a town is 15,200 and is growing 2% each year. Write an equation to model the population growth. Predic

Dvinal [7]

1. So the current population of the town is 15 200 and is growing per year with 2%.
Find the population number after 10 years.
First, let’s find the value of 2% in decimal form
=> 2/100
=> 0.02

Now, let’s try to solve
Population = 15 200 ( 1 + (0.02 x 10) )
Population = 15 200 ( 1 + 0.2 )
Population = 15 200 + 3040
Population = 18 240
Thus, in 10 years, the town’s population will increase to 18 240.

3 0

3 years ago

Read 2 more answers

The pool is located at (0,0) to get to your house from the pool you walk three blocks west and one block north what ordered pair

ira [324]

Answer:

(-3, 1) quadrant II (2)

Step-by-step explanation:

An image of the coordinate plane is show. The quadrants start at the top right and move around in the counter-clockwise direction. The x-axis is horizontal (side to side) and y-axis is vertical (up and down). Starting at the origin of the coordinate plane (0, 0) and going three blocks west (left) would put you at -3 on the x-axis. If you then proceed to go north (up) +1, you would now be at point (-3, 1) which is a (-x, +y) or in quadrant II.

8 0

3 years ago

Divide (x^3+2x^2-x-2) by (x-1)

Ymorist [56]

$\frac{x^3+2x^2-x-2}{(x-1)} =x^2+3x+2 \\ \\ x^3+2x^2-x-2= \\= x^2(x+2)-(x+2) \\ =(x+2)(x^2-1)=(x+2)(x-1)(x+1) \\ \\ \frac{x^3+2x^2-x-2}{(x-1)} = \frac{(x+2)(x-1)(x+1)}{x-1} =(x+2)(x+1)=x^2+3x+2$

7 0

2 years ago