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padilas [110]
3 years ago
5

write each of the following fraction as equivalent fractions with a denominator of 10 a. 1/2 b. 1/4 c. 3/30 d. 12/30​

Mathematics
1 answer:
monitta3 years ago
5 0

9514 1404 393

Answer:

  a. 5/10

  b. 2.5/10

  c. 1/10

  d. 4/10

Step-by-step explanation:

To find the numerator, multiply each fraction by 10.

  a. (1/2)(10) = 5, so 1/2 = 5/10

  b. (1/4)(10) = 2.5, so 1/4 = (2.5)/10 or (5/2)/10

  c. (3/30)(10) = 1, so 3/30 = 1/10

  d. (12/30)(10) = 4, so 12/30 = 4/10

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I need help with this question pls
Andrej [43]

Answer:61.8°

Step-by-step explanation:

Length of arc=(theta)/360 x 2 x π x radius

9.7=(theta)/360 x 2 x 3.14 x 9

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9.7 x 360=56.52(theta)

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Divide both sides by 56.52

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7 0
3 years ago
Expand and simplify<br> (x – 3)(2x - 2)
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6 0
2 years ago
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6 0
2 years ago
Read 2 more answers
Evaluate each finite series for the specified number of terms. 1+2+4+...;n=5
zaharov [31]

Answer:

31

Step-by-step explanation:

The series are given as geometric series because these terms have common ratio and not common difference.

Our common ratio is 2 because:

1*2 = 2

2*2 = 4

The summation formula for geometric series (r ≠ 1) is:

\displaystyle \large{S_n=\frac{a_1(r^n-1)}{r-1}} or \displaystyle \large{S_n=\frac{a_1(1-r^n)}{1-r}}

You may use either one of these formulas but I’ll use the first formula.

We are also given that n = 5, meaning we are adding up 5 terms in the series, substitute n = 5 in along with r = 2 and first term = 1.

\displaystyle \large{S_5=\frac{1(2^5-1)}{2-1}}\\\displaystyle \large{S_5=\frac{2^5-1}{1}}\\\displaystyle \large{S_5=2^5-1}\\\displaystyle \large{S_5=32-1}\\\displaystyle \large{S_5=31}

Therefore, the solution is 31.

__________________________________________________________

Summary

If the sequence has common ratio then the sequence or series is classified as geometric sequence/series.

Common Ratio can be found by either multiplying terms with common ratio to get the exact next sequence which can be expressed as \displaystyle \large{a_{n-1} \cdot r = a_n} meaning “previous term times ratio = next term” or you can also get the next term to divide with previous term which can be expressed as:

\displaystyle \large{r=\frac{a_{n+1}}{a_n}}

Once knowing which sequence or series is it, apply an appropriate formula for the series. For geometric series, apply the following three formulas:

\displaystyle \large{S_n=\frac{a_1(r^n-1)}{r-1}}\\\displaystyle \large{S_n=\frac{a_1(1-r^n)}{1-r}}

Above should be applied for series that have common ratio not equal to 1.

\displaystyle \large{S_n=a_1 \cdot n}

Above should be applied for series that have common ratio exactly equal to 1.

__________________________________________________________

Topics

Sequence & Series — Geometric Series

__________________________________________________________

Others

Let me know if you have any doubts about my answer, explanation or this question through comment!

__________________________________________________________

7 0
2 years ago
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