Answer:
I don't know how to do please let me I will try solve the question
Answer:
- Please see the attached picture for full solution!:)
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Answer:
A. (x−2y)(y−3x)
=(x+−2y)(y+−3x)
=(x)(y)+(x)(−3x)+(−2y)(y)+(−2y)(−3x)
=xy−3x2−2y2+6xy
=−3x2+7xy−2y2
B. (2p+3)(p2−4p−7)
=(2p+3)(p2+−4p+−7)
=(2p)(p2)+(2p)(−4p)+(2p)(−7)+(3)(p2)+(3)(−4p)+(3)(−7)
=2p3−8p2−14p+3p2−12p−21
=2p3−5p2−26p−21
Hope it helps
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Answer:
x=13
Step-by-step explanation:
First, you add the x's together: 2x+x=3x
Now you have:3x-1=38
Add 1 to both sides: 3x=39
1 cancel on the left side of the equation
Divide 3 on both sides: x=39/3
3 cancels on the left side and 39 divided by 3 is 13:
x=13
Hope this helps!