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3 years ago

Topic: Multiplying and dividing fractionsanswer 2 of the questions71 points

Mathematics

2 answers:

nlexa [21]3 years ago

5 0

Answer:

7. 9 kg

a) 4 cm

Step-by-step explanation:

7. ¾ of 12

¾×12

3×3 = 9

a) ⅔ of 6

⅔×6

2×2

4 cm

skad [1K]3 years ago

3 0

7. Multiply the mass of the porcupine by the raccoons portion:

12 x 3/4 = (12 x 3)/4 = 36/4 = 9kg.

8. Multiply both numbers:

6 x 2/3 = (6x2)/3 = 12/3 = 4cm

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Three sets have 5, 10, 15 elements, respectively. How many elements can their union and intersection have?

Degger [83]

Answer:

$Union = 15$

Step-by-step explanation:

Given

$n(A) = 5; n(B) = 10; n(C) = 15$

Solving (a): Possible union elements

This is the represented by element with the largest number of the sets

i.e.

$Union = 15$

Solving (b): Possible intersection elements

This is the represented by element with the least number of the sets

i.e.

$Intersection = 5$

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3 years ago

Challenge Yossi used to have a square garage with 264 ftof floor space. He recently built an

Lady_Fox [76]

Answer:

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2 years ago

Multiply and Simplify<br> (x-4)(x^2 - 5x - 6)

kirill [66]

Answer:

x^3 -9x^2 +14x +24

Step-by-step explanation:

(x-4)(x^2 - 5x - 6)

Multiply the x by everything in the second term

x * (x^2 - 5x - 6)

x^3 -5x^2 -6x

Multiply the -4 by everything in the second term

-4 * (x^2 - 5x - 6)

-4x^2 +20x +24

Add everything together

I like to line them up vertically

x^3 -5x^2 -6x

-4x^2 +20x +24

-------------------------------

x^3 -9x^2 +14x +24

4 0

2 years ago

Read 2 more answers

Help please 10 points!

Alinara [238K]

Answer:

I'm not sure, but it might be 120.

4 0

3 years ago

Two pipes can fill a tank in 19 minutes if both are turned on. If only one is used, it would take 49 minutes longer for the smal

a_sh-v [17]

Answer:

The time taken by smaller pipe to fill the tank alone is 74.2 min

Step-by-step explanation:

Given as :

The time taken by two pipes to fill tank = 19 min

Let the time taken by larger pipe to fill tank = y

And the time taken by smaller pipe to fill tank = x

According to question

The smaller pipe takes 49 minutes longer than larger pipe

I.e x = y + 49

Now,

$\dfrac{1}{x}$ + $\dfrac{1}{y}$ = $\dfrac{1}{49}$

Or, $\dfrac{1}{y + 49}$ + $\dfrac{1}{y}$ = $\dfrac{1}{49}$

Or, $\dfrac{y + 49 + y}{y^{2} + 49 y }$ = $\dfrac{1}{49}$

Or, 2 y + 49 = $\dfrac{y^{2}+49y }{19}$

Or, 19 × ( 2 y + 49 ) = y² + 49 y

Or, 38 y + 931 = y² + 49 y

Or, y² + 49 y - 38 y - 931 = 0

or, y² + 11 y - 931 = 0

Or, Applying quadratic equation method to calculate the value of y

so, y = $\frac{- b \pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

Or, y = $\frac{- 11 \pm \sqrt{11^{2}-4\times 1\times (-931)}}{2\times 1}$

Or, y = $\frac{- 1 \pm \sqrt{121+3724}}{2}$

or, y = $\frac{- 1 \pm \sqrt{3845}}{2}$

or, y = $\frac{- 1 \pm 62.008}{2}$

∴ y = 25.2 , - 36.5

So, The time taken by larger pipe = y = 25.2 min

and the time taken by smaller pipe to fill the tank = y + 49 = 25.2 + 49 = 74.2 min

Hence The time taken by smaller pipe to fill the tank alone is 74.2 min answer

6 0

2 years ago