How do you solve thus ? 8=8v-4(v+8)

1 answer:

8 0

8 = 8v - 4 (v + 8)

Distribute the 4 through the parentheses

8 = 8v - 4v - 32

combine like terms

8 = 4v - 32

add 32 to both sides

8 + 32 = 4v -32 + 32

combine like terms

40 = 4v

divide each side by 4

40/10 = v

4 = v

v= 4

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The point-slope form of the equation of the line that passes through (-4,-3) and (12, 1) is y-1= 1/4(x-12). what is the stadard

Monica [59]

Answer:

x - 4y = 8

Step-by-step explanation:

Since the Point-Slope Formula is already given to you, convert it to Slope-Intercept Form, and you do that by doing this:

y - 1 = ¼(x - 12) >> y - 1 = ¼x - 3

y - 1 = ¼x - 3

+ 1 + 1

--------------

y = ¼x - 2 >> Slope-Intercept Form

After doing this, you are ready to convert to Standard Form, and you do that by doing this:

y = ¼x - 2

-¼x -¼x

-----------

-¼x + y = -2

Now unfortunately, we do not want fractions as our coefficients, so the way to eliminate the fraction is to multiply the equation by the Multiplicative Inverse of -¼, which is -4:

-4[-¼x + y = -2] >> x - 4y = 8 → New equation without fractions

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