Answer:
p value from chi square = 0.081
Step-by-step explanation:
Given that sociologists say the percentage of the classic music lovers is about 5%. From the survey, we know that only 83 out of 2000 people listen to the classic music. Let denote the proportion of the classic music lovers. The hypotheses are H0: p=0.05 vs Ha: p≠0.05
p value = 0.09
Instead of this if we do chi square
H0: Proportion of music lovers is 5% and non music lovers is 95%
Ha: Proportions are not as per the estimate
(Two tailed chi square test)
Observed 83 1917 2000
Expected 100 1900 2000
O-E -17 17 0
chi square
(O-E)^2/E 2.89 0.1521 3.0421
df =1
p value from chi square = 0.081
Though p value is not exactly the same, the conclusion in both tests are the same
Answer:
Step-by-step explanation:
1) Let the random time variable, X = 45min; mean, ∪ = 30min; standard deviation, α = 15min
By comparing P(0 ≤ Z ≤ 30)
P(Z ≤ X - ∪/α) = P(Z ≤ 45 - 30/15) = P( Z ≤ 1)
Using Table
P(0 ≤ Z ≤ 1) = 0.3413
P(Z > 1) = (0.5 - 0.3413) = 0.1537
∴ P(Z > 45) = 0.1537
2) By compering (0 ≤ Z ≤ 15) ( that is 4:15pm)
P(Z ≤ 15 - 30/15) = P(Z ≤ -1)
Using Table
P(-1 ≤ Z ≤ 0) = 0.3413
P(Z < 1) = (0.5 - 0.3413) = 0.1587
∴ P(Z < 15) = 0.1587
3) By comparing P(0 ≤ Z ≤ 60) (that is for 5:00pm)
P(Z ≤ 60 - 30/15) = P(Z ≤ 2)
Using Table
P(0 ≤ Z ≤ 1) = 0.4772
P(Z > 1) = (0.5 - 0.4772) = 0.0228
∴ P(Z > 60) = 0.0228
Radius = 100m
Circumference of a circle = 2πr
= 2 × π× 100
=628.31m
Answer:
y=2x-14
Step-by-step explanation:
Gradient as m(for 1st line m1 and m2 for 2nd line)
m1/m2=-1
m1=(-1)*(-2)=2
y-(-2)/x-6=2
y+2/x-6=2
y+2=2x-12
y=2x-14
103.468
Since 4 rounds down:
103
Hope this helps!
