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ratelena [41]
4 years ago
15

The area of a rectangular prism is 38 1/4 square meters the width of the garden is 4 1/2 meters find the length of the garden

Mathematics
2 answers:
OLEGan [10]4 years ago
5 0
Well the answer is 8 1/2 because 38 1/4 as a decimal is 38.25 and 4 1/2 as decimal is 4.5 do if you 38.25/4.5= 8.2 as a fraction it would be 8 1/2
bagirrra123 [75]4 years ago
3 0
It's 3/5 because of the lenghth
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A taxi is rented by a group of x people for $40 and the cost is shared equally. If there is one less person in the group then th
anzhelika [568]

Answer:

X = 5  

Step-by-step explanation:

I think there a problem with the question, If there is one less person in the group then the payment by each remaining person is must more than $2 than the previous, because the rent cost unchanged but the number of people in the group decreased.

Before, cost per person : \frac{40}{x}

After cost per person:  = \frac{40}{x -1 }

However, the payment by each remaining person is more than $2 than the previous, so

\frac{40}{x -1 }  =   \frac{40}{x}  + 2

<=> 2x^{2} - 2x -40 = 0

<=> X = 5  

3 0
3 years ago
In how many unique ways can the seven letters in the word MINIMUM be arranged, if all the letters are used each time
slega [8]

The number of unique ways or permuations to arrange the seven letters in MINIMUM is all the letters are used each time is 420.

According to the given question.

We have a word MINIMUM.

Here, there are 7 letters in "MINIMUM" .

Now, in Minimum the number of letters which are repeated and which are not.

M = 3 times

I = 2 times

N = 1 time

U = 1 time

As, we all know if there is no repetitions in a word which is made of n letters, then we can arrange it by n! ways.

But if there is repetition, we use formula

\frac{n!}{n_{1}! n_{2}!..n_{k}!  }

where, n = n_{1} +n_{2} +n_{3} ...+n_{k}

n_{1} is objects of one type

n_{2} is the objects of two types

n_{k} is the objects of k types

Thereofore, the number of unique ways or permuations to arrange the seven letters in MINIMUM is all the letters are used each time

= 7!/ 3!2!

= 7(6)(5)(4)(3!)/3!(2)(1)

= 7(3)(5)(4)

= 420

Hence, the number of unique ways or permuations to arrange the seven letters in MINIMUM is all the letters are used each time is 420.

Find out more information about number of ways and permuations here:

brainly.com/question/15609044

#SPJ4

4 0
1 year ago
Out of 40 students, 2 earned an A,12 earned a B, 6 earned a C and 20 earned a D or an F. What percent of students earned B?
Doss [256]

Answer:

1) 30% 2) 124 yellow buttons

Step-by-step explanation:

1) 12 B’s out of 40 12/40= .3 x 100 = 30

2) 20%, 20/100, .2

620 x .2 = 124

5 0
3 years ago
Read 2 more answers
there are 20 balls numbered 1 to 20.in a bag.if a person selects one at random,what is the probability that the number printed o
frozen [14]

Prime numbers > than 5 are 7, 11, 13, 17, and 19 so 5/20, or 1/4, or 25% chance

4 0
3 years ago
The sides of a rectangle are 3 and 2x + 1. What expression represents the area of the rectangle?
sertanlavr [38]

Answer:

6x + 3.

Step-by-step explanation:

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= 3 *  (2x + 1)

= 6x + 3.

8 0
4 years ago
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