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emmainna [20.7K]
3 years ago
6

11. Caroline wraps packages at a store. She wraps

Mathematics
1 answer:
Eddi Din [679]3 years ago
8 0

Answer:

<em>C. in five hours Caroline wraps an odd number of packages</em>

Step-by-step explanation:

<em>for</em><em> A until hours you would multiply 2 by 9 and 2 by 9 is 18 and that's an even number so it's not A.</em>

A eliminated.

for B in 3 hours 3 by 9 is 27 and that's an odd number so B is automatically eliminated.

<em>for C in 5 hours all you would do is multiply the 9 by 5 and 9 by 5 is 45 and 45 is indeed an odd number so C is your answer.</em>

<em>for D 7 by 9 is 63 and 63 is an odd number so we already know that C is the answer but still we got to check and D is wrong because 63 is not an even number.</em>

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The sum of the first ten terms of a linear sequence is 145. the sum of the next ten term is 445. find the sum of the first four
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The sum of the first four terms of the sequence is 22.

In this question,

The formula of sum of linear sequence is

S_n =\frac{n}{2}(2a+(n-1)d)

The sum of the first ten terms of a linear sequence is 145

⇒ S_{10} =\frac{10}{2}(2a+(10-1)d)

⇒ 145 = 5 (2a+9d)

⇒ \frac{145}{5} =2a+9d

⇒ 29 = 2a + 9d  ------- (1)

The sum of the next ten term is 445, so the sum of first twenty terms is

⇒ 145 + 445

⇒ S_{20} =\frac{20}{2}(2a+(20-1)d)

⇒ 590 = 10 (2a + 19d)

⇒ \frac{590}{10}=2a+19d

⇒ 59 = 2a + 19d -------- (2)

Now subtract (2) from (1),

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⇒ d = \frac{30}{10}

⇒ d = 3

Substitute d in (1), we get

⇒ 29 = 2a + 9(3)

⇒ 29 = 2a + 27

⇒ 29 - 27 = 2a

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⇒ S_4 =\frac{4}{2}(2(1)+(4-1)(3))

⇒ S_4 =2(2+(3)(3))

⇒ S₄ = 2(2+9)

⇒ S₄ = 2(11)

⇒ S₄ = 22.

Hence we can conclude that the sum of the first four terms of the sequence is 22.

Learn more about sum of sequence of n terms here

brainly.com/question/20385181

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