You can first make the equations:
6x+4y=548
y-12=x
Here, you can use the substitution method and you get:
6(y-12)+4y=548
6y-72+4y=548
10y=620
y=62
Then there are 62 student tickets and 50 adult tickets.
6×11=66
11+66=77
so the first number is 11 and the second is 66. together their sum is 77.
There is no mode
because none of them appear the most
Hey, I think an image is needed to answer this question.
Y = 3x + 0 is what i got though check my math to be sure
