Jill is dividing 23 by 9. If she continues the process, what will keep repeating in the quotient?
2 answers:
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Answer:
1) the planning value for the population standard deviation is 10,000
2)
a) Margin of error E = 500, n = 1536.64 ≈ 1537
b) Margin of error E = 200, n = 9604
c) Margin of error E = 100, n = 38416
3)
As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.
Hence, I will not recommend trying to obtain the $100 margin of error in the present case.
Step-by-step explanation:
Given the data in the question;
1) Planning Value for the population standard deviation will be;
⇒ ( 50,000 - 10,000 ) / 4
= 40,000 / 4
σ = 10,000
Hence, the planning value for the population standard deviation is 10,000
2) how large a sample should be taken if the desired margin of error is;
we know that, n = [ ( × σ ) / E ]²
given that confidence level = 95%, so = 1.96
Now,
a) Margin of error E = 500
n = [ ( × σ ) / E ]²
n = [ ( 1.96 × 10000 ) / 500 ]²
n = [ 19600 / 500 ]²
n = 1536.64 ≈ 1537
b) Margin of error E = 200
n = [ ( × σ ) / E ]²
n = [ ( 1.96 × 10000 ) / 200 ]²
n = [ 19600 / 200 ]²
n = 9604
c) Margin of error E = 100
n = [ ( × σ ) / E ]²
n = [ ( 1.96 × 10000 ) / 100 ]²
n = [ 19600 / 100 ]²
n = 38416
3) Would you recommend trying to obtain the $100 margin of error?
As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.
Hence, I will not recommend trying to obtain the $100 margin of error in the present case.
Answer:
$3355
Step-by-step explanation:
Since the job offers starting salary of $2200 and monthly raise of $105 during his first year of training.
∴ a = 2200 and d = 105
Since the general form of A.P is,
a, a + d, a + 2d, a + 3d, .............
Where, is the last term of A.P or his monthly salary at the end of his training and n is the number of terms in a series.
So, the A.P is:
2200, 2200 + 105, 2200 + 2(105) .........
2200, 2305, 2410 ............
Since there is 12 month in a year therefore, n = 12.
. = 2200 + ( 12 - 1) × 105
= 2200 + 11 × 105
= 2200 + 1155
= 3355
∴ . = 3355
So the monthly salary of Jose at the end of his training is 3355$.