Ask question

Ask question

All categories

3 years ago

5

Identify the name and label the parts of the following polynomial: − 2x^4+24^2-10

1 answer:

lianna [129]3 years ago

7 0

-2x^4 + 24x^2 - 10

u have 3 terms.....and since u are only dealing with 1 variable with the highest exponent being 4, then what u have here is a 4th degree trinomial.
U have a lead coefficient of -2.
Ur constant term is -10
And ur middle term (24x^2) has a degree of 2

a cubic binomial.....a binomial has 2 terms and it being cubic means the highest term has a degree of 3
example would be : x^3 - 4

how many constants can a polynomial have ? I am not sure about this one...I wanna say 1 because u can simplify it if it has more then 1...but I am not 100% sure on this one

3x^2 + 6xy -10x^5 + y^6 - 10x^3y^5

when u have a polynomial with more then 1 variable, such as this one, the degree is not the highest exponent, it is the highest term.....-10x^3y^5...u add the exponents....so this term has a degree of 8, and it is the highest one in this problem....so this is an 8th degree polynomial with 5 terms

You might be interested in

State whether each sequence is arithmetic and justify your answer. If the sequence is arithmetic, write a recursive and an expli

nasty-shy [4]

Answer:

Part A

$f(n)=52-12(n-1)$

$f(n)=\left\{\begin{matrix}52\: \:if \: \:n=1 & \\f(n+1)+12& if\: n\geq 2 \end{matrix}\right.$

Part B

$(2,4,8,16,32)\: \:$ Geometric Sequence

Part C

1/4,3/4,5/4,7/4,9/4

$g(n)=\frac{1}{4}+\frac{2}{4}(n-1)\\f(n)=\left\{\begin{matrix}1/4if \: \:n=1 & \\ f(n+1)+2/4& if\: n\geq 2 \end{matrix}\right$

Part D:

$h(n)=1.1+0.4(n-1)\\h(n)=\left\{\begin{matrix}1.1 & if\:n=1 \\ h(n+1)+0.4 & if\:n\geq 2\end{matrix}\right$

Step-by-step explanation:

By definition, an Arithmetic Sequence holds the same difference between each following number.

Part A

$(52,40, 28, 16)\\52-40=12\\40-28=12\\28-16=12\\d=12$

<u>Explicit Formula</u>

To write an explicit formula is to write it as function.

$f(n)=52-12(n-1)$

<u>Recursive Formula</u>

To write it as recursive formula, is to write it as recurrence given to some restrictions:

$f(n)=\left\{\begin{matrix}52\: \:if \: \:n=1 & \\f(n+1)+12& if\: n\geq 2 \end{matrix}\right.$

Part B

$(2,4,8,16,32)\: \:$

Geometric Sequence, since 2*2=4 8*2=16 and 16*2=32 and 8+2=10 8+16=24

Part C

$(\frac{1}{4},\frac{3}{4},\frac{5}{4},\frac{7}{4},\frac{9}{4})\\\$

Arithmetic Sequence, difference

$d=\frac{2}{4}$

<u>Explicit Formula:</u>

$g(n)=\frac{1}{4}+\frac{2}{4}(n-1)$

<u>Recursive Formula</u>

$g(n)=\left\{\begin{matrix}\frac{1}{4} &if\:n=1 \\ g(n+1)+\frac{2}{4} &if\: n\geq 2\end{matrix}\right.$

Part D

(1.1,1.5,1.9,2.3,2.7) Arithmetic Sequence, difference d=0.4

<u>Explicit formula</u>

$h(n)=1.1+0.4(n-1)\\$

<u>Recursive Formula</u>

$h(n)=\left\{\begin{matrix}1.1 &if\:n=1 \\ h(n+1)+0.4 &if\: n\geq 2\end{matrix}\right.$

6 0

3 years ago

What's the product of 70x6000

MA_775_DIABLO [31]

The product of 70 and 6000 is 420,000.

4 0

3 years ago

The sum of 5 consecutive integers is 265. What is the fifth number in this sequence ?

Yanka [14]

Hello,
Let's assume n,n+1,n+2,n+3,n+4 the 5 numbers

n+(n+1)+...+(n+4)=5n+10=265
5n=265-10
5n=255
n=51
The 5th number is 51+4=55

6 0

3 years ago

Ayuda :c aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

Elan Coil [88]

Answer:

1) 2x^4/343

2) 2x^6/225

3) 2x^12/25

4) 5x^20/16807

Step-by-step explanation:

Hope this helps!

3 0

2 years ago

HELP!!! 40 points for right answer! i will upvote brainliest!!

krok68 [10]

It is C: Given, Reflexive Property

4 0

3 years ago

Read 2 more answers