Question

For f (x) = 3x +1 and g(x) = x^2-6, find (g/f)(x)

Answer 1

Answer:

$(g/f) (x) =\frac{x^2-6}{3x+1}$

Step-by-step explanation:

We have the following functions

$f (x) = 3x+1$

$g (x) = x^2-6$

To find $(g/f)(x)$ we must divide the function g(x) with the function f(x)

Then we perform the following operation

$(g/f) (x) =\frac{x^2-6}{3x+1}$

Finally we have that:

$(g/f) (x) =\frac{x^2-6}{3x+1}$

For $x \neq -\frac{1}{3}$