Answer: y=-(1/8)x+(21/2)
Explanation:
The new equation’s slope needs to be perpendicular to y=8x-1
To get the new slope, we take the negative reciprocal of the slope from above
8 —> -1/8
Now we have y=-(1/8)x+b but it needs to pass through (4,10), so we need to find the value of b that makes this possible.
Since (4,10) is in the form of (x,y) we can plug in these values into the new equation to solve for b:
y=-(1/8)x+b
10=-(1/8)4+b
10=(-1/2)+b
b=(21/2)
Now put b back into the new equation
y=-(1/8)x+b
y=-(1/8)x+(21/2)
Answer:
u = (-21)/20
Step-by-step explanation:
Solve for u:
u + 1/4 = (-4)/5
Put each term in u + 1/4 over the common denominator 4: u + 1/4 = (4 u)/4 + 1/4:
(4 u)/4 + 1/4 = -4/5
(4 u)/4 + 1/4 = (4 u + 1)/4:
1/4 (4 u + 1) = -4/5
Multiply both sides of (4 u + 1)/4 = (-4)/5 by 4:
(4 (4 u + 1))/4 = (-4)/5×4
4×(-4)/5 = (4 (-4))/5:
(4 (4 u + 1))/4 = (-4×4)/5
(4 (4 u + 1))/4 = 4/4×(4 u + 1) = 4 u + 1:
4 u + 1 = (-4×4)/5
4 (-4) = -16:
4 u + 1 = (-16)/5
Subtract 1 from both sides:
4 u + (1 - 1) = (-16)/5 - 1
1 - 1 = 0:
4 u = (-16)/5 - 1
Put (-16)/5 - 1 over the common denominator 5. (-16)/5 - 1 = (-16)/5 - 5/5:
4 u = (-16)/5 - 5/5
-16/5 - 5/5 = (-16 - 5)/5:
4 u = (-16 - 5)/5
-16 - 5 = -21:
4 u = (-21)/5
Divide both sides by 4:
u = ((-21)/4)/5
5×4 = 20:
Answer: u = (-21)/20
The student with the correct answer is Dylan who says the decimal should be placed between the 8 and 0.
This is base on the estimation that 3.01 is a two decimal place number, so the product 18.06 should also be in 2 decimal place.
<h3>How to find product of decimal number?</h3>
A decimal number is a number expressed in the decimal system (base 10).
Place value:
- Ten thousand
- Thousand
- Hundred
- Ten
- ones
- . decimal point
- tenth
- hundredths
- thousandth
- ten thousandth
- hundred thousandth
6 × 3.01
3.01
- 3 = ones
- . = decimal point
- 0 = tenth
- 1 = hundredth
6 × 3.01
= 18.06
Therefore, Lucas is incorrect with his answer that the decimal should be placed between the 1 and 8.
Read more on decimal number:
brainly.com/question/1827193
#SPJ1
Answer:
I believe it is AAS but I'm not 100% so if I'm wrong I would like to apologies ahead of time.
I hope this is good enough:
