Can you help the picture is in the file provided
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Answer: The test statistic needed to test this claim= 10.92
Step-by-step explanation:
We know that the probability of giving birth to a boy : p= 0.5
i..e The population proportion of giving birth to a boy = 0.5
As per given , we have
Null hypothesis :
Alternative hypothesis :
Since is right-tailed , so the hypothesis test is a right-tailed z-test.
Also, it is given that , the sample size : n= 291
Sample proportion:
Test statistic : , where n is sample size ,
is sample proportion and p is the population proportion.
i.e. the test statistic needed to test this claim= 10.92
Critical value ( one-tailed) for 0.01 significance level =
Decision : Since Test statistic value (10.92)> Critical value (2.326), so we reject the null hypothesis .
[When test statistic value is greater than the critical value , then we reject the null hypothesis.]
Thus , we concluded that we have enough evidence at 0.01 significance level to support the claim that the YSORT method is effective in increasing the likelihood that a baby will be a boy.
Answer:
Step-by-step explanation:
Since 2 of the 3 binomials are identical I would start the distribution there.
(1 + 4i)(1 + 4i) =
I'm sure you have learned in class by now that i-squared is = to -1, so we can make that substitution:
1 + 8i + 16(-1) which simpifies to
1 + 8i - 16 which simplifies further to
-15 + 8i. Now we need to FOIL in the last binomial:
(-15 + 8i)(-4 + 4i) =
Combine like terms to get
Again make the substitution of i-squared = -1:
60 - 92i + 32(-1) which simplifies to
60 - 92i - 32 which simpifies, finally, to a solution of:
28 - 92i