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4 years ago

1 Simplify the following expression. 2482 832 A. 23 8 2 OB. 2585 Oc. 8 23 OD. 25 85

Mathematics

1 answer:

NikAS [45]4 years ago

7 0

Answer:

jhigufytduhguiyoutyfdtyxrfdgfhcjvhlkuiyftdyrtzfsgvhuyiftucgc

Step-by-step explanation:

jbhvcxzddgnxfh gnvb,

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The polygons are similar. Find the missing side length.

zloy xaker [14]

Answer:

Step-by-step explanation:

Since triangles are similar, so their corresponding sides would be in proportion.

Therefore,

$\frac{24}{32} = \frac{33}{?} \\ \\ \\ ? = \frac{32 \times 33}{24} \\ \\ ? = \frac{4\times 33}{3} \\ \\ ? = 4\times 11 \\ \\ ? = 44 \: units$

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3 years ago

PLease evaluate this math problem for me!!

umka2103 [35]

8(1/4)

=(8/1)

=(8)(1)/(1)(4)

=8/4

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3 years ago

30tens-3tens3tenths

Pachacha [2.7K]

300 - 30 3/10 = 269 7/10

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3 years ago

1. Storing milk at temperatures colder than 35°F can affect its quality of taste. However, storing milk at temperatures warmer t

Mazyrski [523]

Answer:

Part (A): The required inequality is T < 35 or t >40.

Part (B): The correct option is C) Only x=7.

Part (C) |x+1|+5=2 has no solution; |4x+12|=0 has one solution; |3x|=9 has two solution.

Step-by-step explanation:

Consider the provided information.

Part (A)

Storing milk at temperatures colder than 35°F can affect its quality of taste. However, storing milk at temperatures warmer than 40°F is an unsafe food practice.

The union is written as A∪B or “A or B”.

The intersection of two sets is written as A∩B or “A and B”

We need to determine the inequalities represent the union of these improper storage.

That means we will use A∪B or “A or B”.

The improper storage temperatures is when temperature is less than 35°F or greater than 40°F.

Hence, the required inequality is T < 35 or t >40.

Part (B) 15| x-7|+4=10|x-7|+4

Solve the inequality as shown below:

Subtract 4 from both sides.

$15| x-7|+4-4=10|x-7|+4-4$

Subtract 10|x-7| from both sides

$5\left|x-7\right|=0\\\left|x-7\right|=0\\x=7$

Hence, the correct option is C) Only x=7.

Part (C) Match the solution,

$\left|x+1\right|+5=2$

Subtract 2 from both sides.

$\left|x+1\right|=-3$

Absolute value cannot be less than 0.

Hence, |x+1|+5=2 has no solution.

$|4x+12|=0$

$4x+12=0$

$x=-3$

Hence, |4x+12|=0 has one solution.

$|3x|=9$

$\mathrm{If}\:|u|\:=\:a,\:a>0\:\mathrm{then}\:u\:=\:a\:\quad \mathrm{or}\quad \:u\:=\:-a$

$3x=-9\quad \mathrm{or}\quad \:3x=9\\x=-3\quad \mathrm{or}\quad \:x=3$

Hence, |3x|=9 has two solution.

3 0

3 years ago

The question that says " a school has 1200 pupils "

Sonja [21]

How many girls like sports? well, what's 2/5 of 1200? well, is just their product, 2/5 * 1200.

how many boys like sports? well, what's 3/5 of 1200? 3/5 * 1200.

$\bf \cfrac{2}{5}\cdot 1200\implies \cfrac{2\cdot 1200}{5}\implies \cfrac{2400}{5}\implies \stackrel{girls}{480}
\\\\\\
\cfrac{3}{5}\cdot 1200\implies \cfrac{3\cdot 1200}{5}\implies \cfrac{3600}{5}\implies \stackrel{boys}{720}
\\\\\\
\textit{how many }\stackrel{students}{pupils}\textit{ like sports?}\qquad 480 + 720$

8 0

3 years ago

1 Simplify the following expression. 2482 832 A. 23 8 2 OB. 2585 Oc. 8 23 OD. 25 85​

1 Simplify the following expression. 2482 832 A. 23 8 2 OB. 2585 Oc. 8 23 OD. 25 85