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Leya [2.2K]
3 years ago
15

The formula F = 1.8C + 32 gives the temperature in degrees Fahrenheit (F) for a given temperature in degrees Celsius (C). There

is one temperature for which the number of degrees Fahrenheit is equal to the number of degrees Celsius. Complete the equation you can solve to find that temperature and then use it to find the temperature. Use the variable C to represent the number of degrees Celsius where degrees Fahrenheit and degrees Celsius are the same. The equation is . The temperature for which the number of degrees Fahrenheit is equal to the number of degrees Celsius is °C.

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
7 0

Answer:

-40 °F = -40 °C

Step-by-step explanation:

(1) F = 1.8 C + 32

If the Fahrenheit and Celsius temperatures are the same, then

(2)        F = C     Substitute (2) into (1)

            C = 1.8C + 32     Subtract 1.8 C from each side

C – 1.8 C = 32                   Combine like terms

    -0.8C = 32                   Divide each side by -0.8

          C = -32/0.8

(3)      C = -40                  Substitute (3) into (1)

         F = 1.8(-40) + 32

         F = -72 + 32

        F = -40

So, -40 °F = -40 °C

The thermometer below shows that -40 °F = -40 °C.

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Step-by-step explanation:

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2 years ago
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I don’t get the kind of math that’s called averages
nignag [31]

Answer:

it's known as statistics

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Step-by-step explanation:

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2 years ago
As a town gets​ smaller, the population of its high school decreases by 4% each year. The senior class has 320 students now. In
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Answer:

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  • 28 years

Step-by-step explanation:

Each year, the class size is multiplied by 1 - 4% = 96% = 0.96. After n years, it has been multiplied by that number n times. Repeated multiplication is signified using an exponent.

Class size (c) can be modeled by ...

  c(n) = 320·0.96^n

__

You want to find n such that c(n) = 100. Put in that value and solve.

  100 = 320·0.96^n

  100/320 = 0.96^n . . . . . . . divide by 320

  log(100/320) = n·log(0.96) . . . . . . . take logs

  log(100/320)/log(0.96) = n ≈ 28.4932

In about 28 years, the class will have 100 students.

8 0
3 years ago
Apply the rules for order of operations to simplify (2-1)+27÷3 <br>a)3<br>b)4<br>c)10/3<br>d)6
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Hiya!

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maxonik [38]

Answer:

a. x² + x - 30 = (x + 6)(x - 5)

b. -3x² + 23x - 14 = -[(3x - 2)(x - 7)]

c. 2x² - 5x + 4 can not factorize by this way

d. 6x² + 10x - 24 = 2[(3x - 4)(x + 3)]

Step-by-step explanation:

* To factor a trinomial in the form ax² ± bx ± c:

- Look at the c term

# If the c term is positive

∵ c = r × s ⇒ r and s are the factors of c

∴ r and s will have the same sign (sign of b)

∵ a = h × k ⇒ h , k are the factors of a

∴ rk + hs = b

∴ (hx + r)(kx + s) ⇒ if b +ve  OR  (hx - r)(kx - s) ⇒ if b -ve

# If the c term is negative

∵ c = r × s ⇒ r and s are the factors of c

∴ r and s will not have the same sign

∵ a = h × k ⇒ h and k are the factors of a

∴ rk - hs = b OR hs - rk = b

(hx + r)(kx - s) OR (hx - r)(kx + s)

* Now lets solve the problem

a. x² + x - 30

∵ ax² + bx + c

∴ a = 1 , b = 1 , c = -30

∵ c is negative

∴ r and s have different signs

∵ a = h × k

∵ 1 = 1 × 1

∴ h = 1 , k = 1

∵ c = r × s

∵ c = -30

∴ r × s = -30

∵ 6 × -5 = -30

∴ r = 6 , s = -5

∴ hs = 6

∴ rk = -5

∵ hs - rk = 6 - 5 = 1 ⇒ same value of b

∴ (x + 6)(x - 5)

* x² + x - 30 = (x + 6)(x - 5)

b. -3x² + 23x - 14 ⇒ take -1 as a common factor

∴ -(3x² - 23x + 14)

∵ ax² + bx + c

∴ a = 3 , b = -23 , c = 14

∵ c is positive

∴ r and s have same sign (-ve) because b is negative

∵ a = h × k

∵ 3 = 3 × 1

∴ h = 3 , k = 1

∵ c = r × s

∵ 14 = 2 × 7

∴ r = 2 , s = 7

∴ hs = 3 × 7 = 21

∴ rk = 2 × 1 = 2

∵ hs + rk = 21 + 2 = 23 ⇒ same value of b

∴ (3x - 2)(x - 7)

* -3x² + 23x - 14 = -[(3x - 2)(x - 7)]

c. 2x² - 5x + 4

∵ ax² + bx + c

∴ a = 2 , b = -5 , c = 4

∵ c is positive

∴ r and s have same sign (-ve) because b is negative

∵ a = h × k

∵ 2 = 2 × 1

∴ h = 2 , k = 1

∵ c = r × s

∵ 4 = 2 × 2

∴ r = 2 , s = 2

∴ hs = 2 × 2 = 4

∴ rk = 2 × 1 = 2

∵ hs + rk = 4 + 2 = 6 ⇒ not same value of b

∴ We can not factorize it

* 2x² - 5x + 4 can not factorize by this way

d. 6x² + 10x - 24 ⇒ take 2 as a common factor

∴ 2(3x² + 5x - 12)

∵ ax² + bx + c

∴ a = 3 , b = 5 , c = -12

∵ c is negative

∴ r and s have different signs

∵ a = h × k

∵ 3 = 3 × 1

∴ h = 3 , k = 1

∵ c = r × s

∵ -12 = -4 × 3

∴ r = -4 , s = 3

∴ hs = 3 × 3 = 9

∴ rk = -4 × 1 = -4

∵ hs - rk = 9 - 4 = 5 ⇒ same value of b

∴ (3x - 4)(x + 3)

* 6x² + 10x - 24 = 2[(3x - 4)(x + 3)]

4 0
3 years ago
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