Answer:
Step-by-step explanation:
2 cos x + √ 2 = 0
2 cos x = -√ 2
cos x = -√ 2 / 2
x = arcCos( -√ 2 / 2 )
so to solve we have to use "co-terminal " angles .. do you know what I'm saying? do you understand the words coming out of my mouth :DDDDD OKay back to math and not movie lines .. :P
x = arcCos( √ 2 / 2 )
x = 45 °
now find the "co terminal" angle that is on 45 ° but in the correct quadrant... since the -√ 2 is negative.. we now that we go down the y axis.. but also positive on the x axis.. soooo.. that put the angle in the 4th quadrant... so this is an angle of 315° if we go in the CCW ( counter clock wise ) direction but it's also -45° in the CW (clock wise ) direction
below is the table to remember the trig special angles
notice how it's 1,2,3,4 .. so it's super easy to remember.. the trig books don't show you this "trick" :P
copy and paste this to your computer some where handy
Sin(0) = 0/2 =0
Sin(30)=
/2 = 1/2
Sing(45) =
/2 =
/2
Sin(60)=
/2 =
/2
Sin(90)=
/2 = 1
Cos is exactly the same but counts backwards from 90°
Cos(90) = 0/2 = 0
Cos(60) =
/2 = 1/2
Cos(45) =
/2 =
/2
Cos(30) =
/2 =
/2
Cos(0) =
/2 = 1
-23 over 5 ÷ 11 over 5
-23 × 5 over 5 × 5
-115 over 55
Therefore, your answer would be: -2 and 1 over 11
Answer:
Bruh your in high school yo know this stuff just make everything a decimal to get your answer. Lol you really forgot this?
Step-by-step explanation:
Your answer would be 252 Hope this helps
Answer:
(0, -6)
Step-by-step explanation:
Given the following systems of linear equations;
3x - 2y = 12 ...... equation 1
16x - 4y = 24 ........ equation 2
We would solve for the solution using the elimination method;
Multiplying eqn 1 by 2, we have;
2 * (3x - 2y = 12)
6x - 4y = 24
16x - 4y = 24
Subtracting the two equations, we have;
(6x - 16x) + (-4y -[-4y]) = (24 - 24)
-10x - 0 = 0
-10x = 0
x = -0/10 = 0
Next, we would find the value of y;
3x - 2y = 12
3(0) - 2y = 12
0 - 2y = 12
-2y = 12
y = -12/2
y = -6
Check:
3x - 2y = 12
3(0) - 2(-6) = 12
0 - (-12) = 12
12 = 12
Note: the options provided for this questions are incorrect or inappropriate.