Answer: yes they have a proportional relationship
Step-by-step explanation:
Ratios are proportional if they represent the same relationship. One way to see if two ratios are proportional is to write them as fractions and then reduce them. If the reduced fractions are the same, your ratios are proportional.
Step one : let us test say c=1
F=9/5*1+32
F=9/5+32
F=1.8+32
F=33.8
Say c=2
F=9/5*2+32
F=9/10+32
F=0.9+32
F=32.9
Observe that as c increases
F reduces Hence they have a proportional relationship
-<em><u>samuelonum1</u></em>-
Not my answer/ please give brainlist
recall that a cube has all equal sides, check the picture below.
![\bf \textit{volume of a cube}\\\\ V=x^3~~ \begin{cases} x=side's~length\\[-0.5em] \hrulefill\\ V=5.12 \end{cases}\implies 5.12=x^3 \\\\\\ \sqrt[3]{5.12}=x\implies 1.72354775\approx x](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cube%7D%5C%5C%5C%5C%0AV%3Dx%5E3~~%0A%5Cbegin%7Bcases%7D%0Ax%3Dside%27s~length%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0AV%3D5.12%0A%5Cend%7Bcases%7D%5Cimplies%205.12%3Dx%5E3%0A%5C%5C%5C%5C%5C%5C%0A%5Csqrt%5B3%5D%7B5.12%7D%3Dx%5Cimplies%201.72354775%5Capprox%20x)
Get into form (x-h)^2=4p(y-k)
vetex is (h,k)
so
1/2(x-7)^2=y+4
times 2 both sides
(x-7)^2=2(y+4)
(x-7)^2=4(1/2)(y-(-4))
vertex is (7,-4)
Step-by-step explanation:
the missing side length is 6..........
