A = 1/2 * b * h
b = 14
h = 12
A = 1/2 * 14 * 12
A = 7 * 12 = 84 mm^2
Answer:
Step-by-step explanation:
From the picture attached,
∠4 = 45°, ∠5 = 135° and ∠10 = ∠11
Part A
∠1 = ∠4 = 45° [Vertically opposite angles]
∠1 + ∠3 = 180° [Linear pair of angles]
∠3 = 180° - ∠1
= 180° - 45°
= 135°
∠2 = ∠3 = 135° [Vertically opposite angles]
∠8 = ∠5 = 135° [Vertically opposite angles]
∠5 + ∠6 = 180° [Linear pair of angles]
∠6 = 180° - 135°
∠6 = 45°
∠7 = ∠6 = 45° [Vertically opposite angles]
By triangle sum theorem,
m∠4 + m∠7 + m∠10 = 180°
45° + 45° + m∠10 = 180°
m∠10 = 180° - 90°
m∠10 = 90°
m∠10 = m∠12 = 90° [Vertically opposite angles]
m∠10 = m∠11 = 90° [Given]
Part B
1). ∠1 ≅ ∠4 [Vertically opposite angles]
2). ∠7 + ∠5 = 180° [Linear pair]
3). ∠9 + ∠10 = 180° [Linear pair]
Add the two distances that she walked
x+0.6
answer: C
Multiply the numerators and the denominators
15/120 = 3/24 = 1/8
Answer:
The p-value of the test is 0.023.
Step-by-step explanation:
In this case we need to determine whether the addition of several advertising campaigns increased the sales or not.
The hypothesis can be defined as follows:
<em>H₀</em>: The stores average sales is $8000 per day, i.e. <em>μ</em> = 8000.
<em>Hₐ</em>: The stores average sales is more than $8000 per day, i.e. <em>μ</em> > 8000.
The information provided is:

As the population standard deviation is provided, we will use a z-test for single mean.
Compute the test statistic value as follows:

The test statistic value is 2.
Decision rule:
If the p-value of the test is less than the significance level then the null hypothesis will be rejected.
Compute the p-value for the two-tailed test as follows:

*Use a z-table for the probability.
The p-value of the test is 0.023.