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Karolina [17]
2 years ago
13

Please I need the answer very fast ​

Mathematics
1 answer:
tatyana61 [14]2 years ago
7 0

Answer:

1 - cosΘ

Step-by-step explanation:

using the identity

sin²x + cos²x = 1 , then

sin²x = 1 - cos²x

\frac{sin^20}{1+cos0}

= \frac{1-cos^20}{1+cos0} ← factor 1 - cos²Θ as a difference of squares

= \frac{(1-cos0)(1+cos0)}{1+cos0} ← cancel 1 + cosΘ on numerator/ denominator

= 1 - cosΘ

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Find points and graph the following equation. Is this a linear graph? -5x + 6y = 2
anastassius [24]

Answer:

Yes

Step-by-step explanation:

It is a linear graph.

4 0
3 years ago
What is the value of 5k + m when k = -3 and m = -<br> -9?<br> A. -60<br> B. -30<br> C.-24<br> D. -6
sladkih [1.3K]

Answer:

C. -24

Step-by-step explanation:

5k + m \\ k =  - 3 \\ m =  - 9

Plug in values into the given equation

5( - 3) + ( - 9) \\  - 15 - 9 \\  =  - 24

6 0
3 years ago
The product of , and the sum of a number and - 4 is less than or equal to 64.
lozanna [386]

Answer:

6

Step-by-step explanation:

3 0
2 years ago
The vertex of f(x) = 3x ^2+ 5x + 2 is a:<br> minimum<br> maximum<br> none of these
timama [110]

Answer:

minimum

Step-by-step explanation:

Given a quadratic in standard form f(x) = ax² + bx + c ( a ≠ 0 )

• If a > 0 then vertex is a minimum

• If a < 0 then vertex is a maximum

f(x) = 3x² + 5x + 2 ← is in standard form

with a = 3

Since a > 0 then vertex is a minimum

6 0
3 years ago
The weight of a small Starbucks coffee is a normally distributed random variable with a mean of 330 grams and a standard deviati
just olya [345]

Answer:

Weights of at least 340.1 are in the highest 20%.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 330, \sigma = 12

a. Highest 20 percent

At least X

100-20 = 80

So X is the 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.842.

Z = \frac{X - \mu}{\sigma}

0.842 = \frac{X - 330}{12}

X - 330 = 12*0.842

X = 340.1

Weights of at least 340.1 are in the highest 20%.

3 0
3 years ago
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