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11Alexandr11 [23.1K]
3 years ago
7

What is the value of x in the equation (x + 12) = (x + 14) – 3?

Mathematics
2 answers:
vodomira [7]3 years ago
6 0
(x + 12) = (x + 14) - 3

subtract 12 from each side

x = x + 14 - 3 - 12

Now if we subtract x from each side we see that x - x = 0.  Combine the terms left over and we have -1, so

0 = -1

The answer is NO SOLUTION
deff fn [24]3 years ago
6 0

Answer:  There is NO value of 'x' in the given equation.

Step-by-step explanation:  We are given to find the value of 'x' in the equation below:

(x+12)=(x+14)-3~~~~~~~~~~~~~~~~~~~~(i)

Finding the value of 'x' in equation (i) means to find the value of 'x' for which the equation is TRUE.

The solution is as follows:

(x+12)=(x+14)-3\\\\\Rightarrow x+12=x+14-3\\\\\Rightarrow x+12=x+11\\\\\Rightarrow x-x=11-12\\\\\Rightarrow 0=-1,

which can NEVER be true.

So, the given equation has NO solution.

Thus, there is NO value of 'x' in the given equation.

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For the following exercises, find (f ∘ g)(x) and (g ∘ f)(x) for each pair of functions.
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Answer:

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To find $(g \circ f)(x)$, substitute f(x) for x in g(x) and simplify the expression.

Step 1 of 2

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$$\begin{aligned}&(f \circ g)(x)=f(5-6 x) \\&(f \circ g)(x)=3(5-6 x)+2 \\&(f \circ g)(x)=15-18 x+2 \\&(f \circ g)(x)=17-18 x\end{aligned}$$

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$$\begin{aligned}&(g \circ f)(x)=g(3 x+2) \\&(g \circ f)(x)=5-6(3 x+2) \\&(g \circ f)(x)=5-18 x-12 \\&(g \circ f)(x)=-7-18 x\end{aligned}$$

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