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11Alexandr11 [23.1K]
3 years ago
7

What is the value of x in the equation (x + 12) = (x + 14) – 3?

Mathematics
2 answers:
vodomira [7]3 years ago
6 0
(x + 12) = (x + 14) - 3

subtract 12 from each side

x = x + 14 - 3 - 12

Now if we subtract x from each side we see that x - x = 0.  Combine the terms left over and we have -1, so

0 = -1

The answer is NO SOLUTION
deff fn [24]3 years ago
6 0

Answer:  There is NO value of 'x' in the given equation.

Step-by-step explanation:  We are given to find the value of 'x' in the equation below:

(x+12)=(x+14)-3~~~~~~~~~~~~~~~~~~~~(i)

Finding the value of 'x' in equation (i) means to find the value of 'x' for which the equation is TRUE.

The solution is as follows:

(x+12)=(x+14)-3\\\\\Rightarrow x+12=x+14-3\\\\\Rightarrow x+12=x+11\\\\\Rightarrow x-x=11-12\\\\\Rightarrow 0=-1,

which can NEVER be true.

So, the given equation has NO solution.

Thus, there is NO value of 'x' in the given equation.

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8 0
2 years ago
Solve the inequality x - 3 > 7
Katen [24]

Answer:

x > 10

Step-by-step explanation:

Given

x - 3 > 7 ( add 3 to both sides )

x > 10

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Answer:

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Step-by-step explanation:

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1 year ago
5^(2x-1)+5^(x+1)=250<br> how do you solve?<br> thank you
zepelin [54]

Answer:

<em>x = 2</em>

Step-by-step explanation:

<u>Exponential Equations</u>

Solve:

5^{2x-1}+5^{x+1}=250

Separate each exponential:

5^{2x}5^{-1}+5^{x}5^{1}=250

Operating:

\displaystyle \frac{5^{2x}}{5}+5^{x}5=250

Multiplying by 5:

5^{2x}+25\cdot5^x=1250

Rearranging:

5^{2x}+25\cdot5^x-1250=0

Recall that:

5^{2x}=(5^{x})^2

(5^{x})^2+25\cdot5^x-1250=0

Calling

y=5^{x}:

y^2+25y-1250=0

Factoring:

(y-25)(y+50)=0

There are two possible solutions:

y=25

y=-50

Since

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y cannot be negative, thus:

5^{x}=25=5^2

The solution is:

x = 2

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Answer:

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