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Lynna [10]
3 years ago
14

-175+5a+8a-10b+2c simplify Please help

Mathematics
1 answer:
blondinia [14]3 years ago
8 0

Answer:

175+13a-10b+2c

Step-by-step explanation:

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Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
Find x - y subtracted from 0 <br> A) -x+y<br> B) -y-x <br> C) x-y
sleet_krkn [62]
First we write the statement step by step to find the correct equation.
 We have then:
 x - y
 subtracted from 0
 (0) - (x-y)
 Resolving:
 (0) - (x-y) = - x + y
 You should notice that different signs are subtracted and equal signs are added.
 Answer:
 A) -x + y
3 0
3 years ago
For which values of x is the expression undefined?<br> x2 – 49<br> x2 – 16
Lyrx [107]

You meant to say x^2 - 49 and the second binomial is x^2 - 16.

x^2 - 49 = (x - 7) (x + 7).

Set each factor to 0 and solve for x individually.

x - 7 = 0

x = 7

x + 7 = 0

x = -7

Do the same for x^2 - 16.

Here is the set up:

x^2 - 16 = (x - 4) (x + 4).

Take it from here.

4 0
3 years ago
What are the values of x and y?<br><br>​
Sergeeva-Olga [200]

Answer:

x=y=61°

Step-by-step explanation:

x=61°(being the pair of vertically opposite angle)

and,

y=61°(being the pair of corresponding angle)

so, x=y=61°

7 0
4 years ago
The track team needs new uniforms. The students plan to sell plush toy bears ​(the school​ mascot) for​ $5 each. The students fi
Bond [772]

Answer:

Company C

Step-by-step explanation:

To find the cost of each bear, you must divide each price by the amount of bears. The prices are shown below:

For company A, each bear costs $2.87.

For company B, each bear costs $2.89.

For company C, each bear costs $2.85.

So, the best buy for the team would be Company C.

Hope this was helpful!

7 0
2 years ago
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