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Slav-nsk [51]
3 years ago
14

What is 1/10 of 547,120 ? O 5471.20 5,471,200 o 547.120 54,712

Mathematics
2 answers:
vodka [1.7K]3 years ago
8 0

Answer:

54712

Step-by-step explanation:

Starting with 547120, move the decimal point one place to the left, obtaining 54712.  (Matches last answer choice)

IRISSAK [1]3 years ago
7 0

Answer:54,712

Step-by-step explanation:

(1/10)*547,120

=54,712

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A survey of all planet Umpt found that 36 beings preferred dubble juice to all the other juices. If 40 being were surveyed all t
frozen [14]

Answer:

90%

Step-by-step explanation:

Number of beings that preferred dubble juice to all the other juices = 36

Number of beings surveyed = x

The percentage of people that preferred dubble juice is calculated as:

(Number of beings who preferred dubble juice/Total number of beings surveyed) × 100

36/40 × 100

= 90%

90% of beings preferred dubble juice.

4 0
3 years ago
What is 34% of 60000000
Ainat [17]

(Lets hope i'm right :p)


The first thing you do is make "34%" into a fraction. That would be 1/34.

After, you would multiply.


1/4 x 60000000/1 = ?

(Use cross multiply if you know)

60000000 divided by 4 = 15000000

1/1 x 15000000/1 = 15000000/1 OR 15000000


Answer: 15000000/1 or 15000000

<em>Tell me if i'm wrong so I can prevent this in the future! Have a lovely day!</em>

                                                                                                     ~Pooch ♥


7 0
3 years ago
Read 2 more answers
Please answer ASAP! Thank you in advance, and remember to wash your hands consistently for 1 minute.
Genrish500 [490]
W=144 I think :). Hope I helped!
3 0
4 years ago
4 + 4 = <br><br><br><br><br> plz help me question below!
STALIN [3.7K]

Answer:

A

Step-by-step explanation:

5y=32

trying to get y by itself

y=32/5

32/5 is the same as 6 and 2/5

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5 0
4 years ago
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What is the probability that at least one of a pair of fair dice lands of 5, given that the sum of the dice is 8?
o-na [289]

Answer:

0.40

Step-by-step explanation:

to find out the probability that at least one of a pair of fair dice lands of 5, given that the sum of the dice is 8

Let A = sum of dice is 8

B = one lands in 5

P(B/A) = P(AB)/P(A) by conditional probability

P(AB) = sum is 8 and one is 5

So (5,3) or (3,5)

P(A) = sum  is 8.

i.e. (2,6) (2,6) (3,5) (5,3) (4,4)

Required probability

= n(AB)/n(A)

=\frac{2}{5} =0.40

4 0
3 years ago
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