(-7,-3) (-1,0) (9,5) and (13,7)
In order to graph the equation, you need some coordinates,
So, put x = 0,
2y = 6. y = 3. Coordinate = (0, 3)
Now, put y = 0,
-x = 6
x = -6 Coordinate (-6, 0)
In short, Just mark that two points and draw a line, graph is done
Hope this helps!
Answer:
C. Test for Goodness-of-fit.
Step-by-step explanation:
C. Test for Goodness-of-fit would be most appropriate for the given situation.
A. Test Of Homogeneity.
The value of q is large when the sample variances differ greatly and is zero when all variances are zero . Sample variances do not differ greatly in the given question.
B. Test for Independence.
The chi square is used to test the hypothesis about the independence of two variables each of which is classified into number of attributes. They are not classified into attributes.
C. Test for Goodness-of-fit.
The chi square test is applicable when the cell probabilities depend upon unknown parameters provided that the unknown parameters are replaced with their estimates and provided that one degree of freedom is deducted for each parameter estimated.
Answer:
5.44 cm³
Step-by-step explanation:
The volume of the hexagonal nut can be found by multiplying the area of the end face by the length of the nut. The end face area is the difference between the area of the hexagon and the area of the hole.
The area of a hexagon with side length s is given by ...
A = (3/2)√3·s²
For s=1 cm, the area is ...
A = (3/2)√3(1 cm)² = (3/2)√3 cm²
__
The area of a circle is given by ...
A = πr²
The radius of a circle with diameter 1 cm is 0.5 cm. Then the area of the hole is ...
A = π(0.5 cm)² = 0.25π cm²
__
The volume is the face area multiplied by the length, so is ...
V = Bh = ((3/2)√3 -0.25π)(3) . . . . . cm³
V = (9/2)√3 -0.75π cm³ ≈ 5.44 cm³
The volume of the metal is about 5.44 cm³.
Answer:
B
Step-by-step explanation:
∠ABC= 180° -142° (adj. ∠s on a str. line)
∠ABC= 38°
∠BAC= 180° -133° (adj. ∠s on a str. line)
∠BAC= 47°
∠ACB= 180° -38° -47° (∠ sum of △)
∠ACB= 95°
n°= 180° -95° (adj. ∠s on a str. line)
n°= 85°
n= 85