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Alchen [17]
3 years ago
5

Need help with this question!

Mathematics
1 answer:
kenny6666 [7]3 years ago
7 0

Answer:

23/3 cubic units

Step-by-step explanation:

The volume of a prism is the product of its base area and it height:

V = (23/4 units^2)(4/3 units) = (4·23)/(4·3) units^3 = 23/3 units^3

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Answer:

(4, -2)

Step-by-step explanation:

You first go to the x axis (The one going left and round). From this, you can see the point is on 4 for the x axis. After that, you look at the y axis (The one going up and down). From this, you can see it is -2. In all, you put it in coordinate form which gives you (4, -2). I hope this helps you!

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Step-by-step explanation:

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Please solve the problem with steps
Debora [2.8K]

Answer:

Infinite series equals 4/5

Step-by-step explanation:

Notice that the series can be written as a combination of two geometric series, that can be found independently:

\frac{3^{n-1}-1}{6^{n-1}} =\frac{3^{n-1}}{6^{n-1}} -\frac{1}{6^{n-1}} =(\frac{1}{2})^{n-1} -\frac{1}{6^{n-1}}

The first one: (\frac{1}{2})^{n-1} is a geometric sequence of first term (a_1) "1" and common ratio (r) " \frac{1}{2} ", so since the common ratio is smaller than one, we can find an answer for the infinite addition of its terms, given by: Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{2} } =\frac{1}{\frac{1}{2} } =2

The second one: \frac{1}{6^{n-1}} is a geometric sequence of first term "1", and common ratio (r) " \frac{1}{6} ". Again, since the common ratio is smaller than one, we can find its infinite sum:

Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{6} } =\frac{1}{\frac{5}{6} } =\frac{6}{5}

now we simply combine the results making sure we do the indicated difference: Infinite total sum= 2-\frac{6}{5} =\frac{10-6}{5} =\frac{4}{5}

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