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labwork [276]
3 years ago
15

Mikel has a poster that she wants to copy onto a mural at school. The dimensions of the poster are shown below.

Mathematics
1 answer:
nata0808 [166]3 years ago
5 0
<h2><u>Answer:</u></h2>

The area of the poster would be <u>20ft².</u>

<h2><u>Step-by-step explanation:</u></h2>
  • First, double both the length and the width.

        LENGTH : 2 x 2 = 4

        WIDTH : 2.5 x 2 = 5

  • Use these new dimensions to work out the area

        4 x 5 = <u>20ft²</u>

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Someone please help me will give brainliest!!!!!
ololo11 [35]
I believe the fastest way to solve this problem is to take any two of the given points and to find the slope and y-intercept of the line connecting those two points.  

Let's choose the 2 given points (-3,16) and (-1,12).
Going from the first point to the second, the increase in x is 2 and the increase in y is actually a decrease:  -4.  Thus, the slope of the line connecting these two points is m = -4/2, or m = -2.

Now use the slope-intercept formula to find the y-intercept, b.

One point on the line is (-3,16), and the slope is m = -2.

Thus, the slope-intercept formula y = mx + b becomes 16 = -2(-3) + b.
Here, b comes out to 10.

So now we have the slope and the y-intercept.  Write the equation:

y = mx + b becomes y=-2x+10.  Which of the four given answer choices is the correct one?
3 0
3 years ago
Los puntajes obtenidos por un grupo de alumnos en un examen de 10 puntos son 3,5,2,6,5,9,5,2,8,6. Para saber el puntaje máximo q
Vikentia [17]

Answer:

Para saber el puntaje máximo que obtuvo el 75% de los alumnos se debe calcular el tercer cuartil.

Step-by-step explanation:

Los Cuantiles (cuartiles, deciles, percentiles) son medidas de localización cuya  función es informar del valor de la variable que ocupará la posición (en tanto por  cien) que interese respecto de todo el conjunto de variables.

Los cuartiles son medidas estadísticas de posición que tienen la  propiedad de dividir la serie estadística en cuatro grupos de números iguales de  términos.

El primer cuartil o cuartil inferior es aquel valor de la variable tal que la cuarta parte (25%) de las observaciones son inferiores o iguales a él, y el resto (75%) es superior o igual. El segundo cuartil es la mediana, ya que se trata del valor localizado en la mitad de la distribución. Finalmente, el tercer cuartil o cuartil superior es un valor tal que las tres cuartas partes de las observaciones son inferiores o iguales a él.

En otras palabras, el primer cuartil Q1, es el valor en el cual o por debajo del cual queda aproximadamente un cuarto (25%) de todos los valores de la sucesión (ordenada); El segundo cuartil Q2 es el valor por debajo del cual queda el 50% de los datos (Mediana), el tercer cuartil Q3 es el valor por debajo del cual quedan las tres cuartas partes (75%) de los datos. Es decir, Q1, Q2 y Q3 determinan los valores correspondientes al 25%, al 50% y al 75% de los datos respectivamente. Q2 coincide con la mediana.

<u><em>Para saber el puntaje máximo que obtuvo el 75% de los alumnos se debe calcular el tercer cuartil.</em></u>

<u><em></em></u>

5 0
3 years ago
PLEASE HELP!<br>Calculate $40^{13} \pmod{85}.$
SVEN [57.7K]
In this type of calculations, we decompose 13 by checking the lowest powers of the base, that is 40. for example we check 40^2, or 40^3 and compare it to 85

Notice

40*40*40=64,000

so we check how many time does 85 fit into 64,000:

64,000/85=752.94

85*753=64,005;       64000-64,005=-5

this means that 

40^{3} =-5\pmod{85}

thus

40^{13} =40^{3*4+1}={(40^{3})}^{4}*40=(-5)^{4}*40 \pmod{85}=\\\\625*40\pmod{85}=(7*85+30)*40\pmod{85}=30*40\pmod{85}\\\\=1200\pmod{85}=(14*85+10)\pmod{85}=10\pmod{85}


Answer: 10 (mod85)

Remark, the set of all solutions is:

{......-75, 10, 95, .....}, that is 85k +10
7 0
3 years ago
Please I need help it’s an emergency
Fofino [41]

Answer:

the answer is 36

Step-by-step explanation:

beacuse if we use the pythagorean theorem for 9 and 12 we get 15 which means that the perimeter is P=9+15+12=36

8 0
3 years ago
Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.
Leni [432]

Answer:  \dfrac{2x^2-1}{x(x^2-1)}

Step-by-step explanation:

The given function : y=\ln(x(x^2 - 1)^{\frac{1}{2}})

\Rightarrow\ y=\ln x+\ln (x^2-1)^{\frac{1}{2}}    [\because \ln(ab)=\ln a +\ln b]

\Rightarrow y=\ln x+\dfrac{1}{2}\ln (x^2-1)}  [\because \ln(a)^n=n\ln a]

Now , Differentiate both sides  with respect to x , we will get

\dfrac{dy}{dx}=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})\dfrac{d}{dx}(x^2-1) (By Chain rule)

[Note : \dfrac{d}{dx}(\ln x)=\dfrac{1}{x}]

\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x-0)

[ \because \dfrac{d}{dx}(x^n)=nx^{n-1}]

=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x) = \dfrac{1}{x}+\dfrac{x}{x^2-1}\\\\\\=\dfrac{(x^2-1)+(x^2)}{x(x^2-1)}\\\\\\=\dfrac{2x^2-1}{x(x^2-1)}

Hence, the derivative of the given function is \dfrac{2x^2-1}{x(x^2-1)} .

8 0
4 years ago
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