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Sonbull [250]
3 years ago
9

HELP 100 POINTS PLEASE

Mathematics
2 answers:
olga55 [171]3 years ago
8 0

Answer:

ohhhhh a 100 points dam im lucky !

Step-by-step explanation:

Ymorist [56]3 years ago
3 0

w o w 100 points! t h a n k s :D

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Suppose ABC is a right triangle with sides​ a, b, and c and right angle at C. Find the unknown side length using the Pythagorean
Leno4ka [110]

Answer:

a = \sqrt{7}

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.:

<em>Suppose ABC is a right triangle with sides​ a, b, and c and right angle at C. Find the unknown side length using the Pythagorean theorem and then find the values of the six trigonometric functions for angle B. when b=3 and c=4</em>.

My answer:

We will Pythagoras theorem, which states that the sum of squares of two legs of a right triangle is equal to the square of the hypotenuse of right triangle. Because the question says that ABC is a right triangle.

a^2+b^2=c^2

Given that: b=3 and c=4

a^2+3^2=4^2a^2+9=16a^2+9-9=16-9a^2=7

so a = \sqrt{7}

We know that tangent relates opposite side of a right triangle with adjacent side.

\text{tan}(B)=\frac{a}{b}\\\text{tan}(B)=\frac{\sqrt{7}}{3}

Please have a look at the attached photos.

3 0
3 years ago
What is the value of the expression when b= -4 and C=1
babymother [125]

Answer:

B would equal -4

Step-by-step explanation:

7 0
3 years ago
Answer This Mathematics (Hard Mode)<br>522 X 854 = ____​
iren2701 [21]

Answer:

445788

Step-by-step explanation:

OMG too difficult man!!

Thanks to my calculator to solve this hard question

5 0
2 years ago
Read 2 more answers
-2b + 9 = 25<br> ones step and two step equation Screenshot of example
ycow [4]

Answer:

b = -8

Step-by-step explanation:

-2b + 9 =25

-9 = -9

-2b = 16

/-2 /-2

b = -8

3 0
2 years ago
F(x) = (3x + 6) (x - 3)²
Sever21 [200]

f(x)= 3x³ - 18x +9

Algebraic identities are algebraic equations that are true regardless of the value of each variable. Additionally, they are employed in the factorization of polynomials. Algebraic identities are employed in this manner for the computation of algebraic expressions and the solution of various polynomials.

Identity I: (a + b)² = a² + 2ab + b²

Identity II: (a – b)² = a² – 2ab + b²

Identity III: a² – b²= (a + b)(a – b)

Identity IV: (x + a)(x + b) = x² + (a + b) x + ab

Identity V: (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca

Identity VI: (a + b)³ = a³ + b³ + 3ab (a + b)

Identity VII: (a – b)³ = a³ – b³ – 3ab (a – b)

Identity VIII: a³ + b³ + c³ – 3abc = (a + b + c)(a² + b² + c² – ab – bc – ca)

f(x) = (3x + 6) (x - 3)²

      = ( 3x + 6) ( x - 3 )²

      = ( 3x + 6)( x² - 6x + 9)

      = 3x( x² - 6x + 9) + 6( x² - 6x + 9)

      = 3x³ - 6x² + 18x + 6x² - 36x +9

      = 3x³ - 18x +9

To learn more about algebraic expansions, refer to brainly.com/question/4344214

#SPJ9

5 0
2 years ago
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