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Pie
3 years ago
7

Zeus Industries bought a computer for $2280. It is expected to depreciate at a rate of 30% per year. What will the value of the

computer be in 3 years?
Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
8 0
This is an exponential growth/decay problem.  It has a formula, and it doesn't matter which you have...the formula is the same for both, except for the fact that you're rate is decreasing instead of increasing so you will use a negative rate. The formula is this: A = Pe^rt, where A is the ending amount, P is the beginning amount, e is euler's number, r is the rate at which something is growing or dying, and t is the time in years. Our particular formula will look like this: A = 2280e^(-.30*3), Notice we have a negative number in for the rate (and of course it's expressed as a decimal!). First simplify the exponents: -.30*3 = -.9. On your calculator you have a 2nd button and a LN button.  When you hit 2nd-->LN you have "e^( " on your display.  Enter in -.9 and hit enter.  That should give you a display of .4065695.  Now multiply that by 2280 to get 926.98, the value of the computer after it depreciates for 3 years at a rate of 30% per year.
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I am gonna use substitution method.
Solve for y in first equation,
y + 4x = 8
y = 8 -4x
Put the above y value in second equation,
5x + 2y = 13
5x + 2(8-4x) = 13
5x + 16 - 8x = 13
-3x = 13-16
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x = -3/-3
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y + 4(1) = 8
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4 years ago
What is solution to 130 more than or equal to-29 - z
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Answer:

Step-by-step explanation:

130 ≥ -29-z

130 + 29 ≥ -z

159 ≥ -z

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4 years ago
mr somers had twenty pieces of metal that were all the same length. if each piece of metal was 3 1/5 inches long and he put them
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4 years ago
If you answer this for me you will get brainless
kumpel [21]

Answer:

50.27

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