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Bumek [7]
3 years ago
6

I have 12 coins x of them are R5 coins and the rest are R1 coins. An expression in the in terms of x for the number of R1 coins

I have is​
Mathematics
1 answer:
Marrrta [24]3 years ago
7 0

Answer:

ans= 12-x=r1 coin...

Step-by-step explanation:

hope u can do..

You might be interested in
What is the determinant of the coefficient matrix of the system {4x+3y+2z=0 -3x+y+5z=0 -x-4y+3z=0
slava [35]

Answer:

  130

Step-by-step explanation:

You want the determinant of the matrix ...

  \left[\begin{array}{ccc}4&3&2\\-3&1&5\\-1&-4&3\end{array}\right]

One way to figure it is as the difference between the sum of products of the down-diagonals and the sum of products of the up-diagonals:

  D = (4)(1)(3) +(3)(5)(-1) +(2)(-3)(-4) -(-1)(1)(2) -(-4)(5)(4) -(3)(-3)(3)

  = 12 -15 +24 +2 +80 +27

  D = 130

The determinant of the coefficient matrix is 130.

_____

Many scientific and graphing calculators and web sites can perform this calculation for you.

7 0
3 years ago
18 cajas de manzanas y peras fueron llevadas a la escuela. Las peras trajeron 210 kg en 6 cajas. ¿Cuántos kilos de manzanas fuer
Katyanochek1 [597]

Answer:

504 kilos de manzanas fueron llevados a la escuela.

Step-by-step explanation:

Sean x, y la cantidad de cajas de manzanas y peras, respectivamente. De acuerdo con el enunciado, tenemos el siguiente sistema de ecuaciones:

Total de cajas

x+y = 18 (1)

Masa de cada caja de peras

y\cdot m_{P} = 210 (2)

y = 6 (3)

Masa de caja de manzanas

m_{M} = m_{P}+7 (4)

De (2) en (3), tenemos que la masa de cada caja de peras es:

m_{P} = 35\,kg

Por (4), encontramos que la masa de cada caja de manzanas es:

m_{M} = 35\,kg+7\,kg

m_{M} = 42\,kg

Finalmente, de (1) tenemos la cantidad de cajas de manzana:

x = 18-y

x = 12

La cantidad de kilos de manzanas llevada a la escuela se obtiene al multiplicar la cantidad de cajas de manzana por la masa de cada caja:

M = (12)\cdot (42\,kg)

M = 504\,kg

504 kilos de manzanas fueron llevados a la escuela.

7 0
2 years ago
ANSWER PLZ QUICK AND FAST WHAT
Marysya12 [62]

the answer is C

Use the distributive property

3 0
2 years ago
Read 2 more answers
Please Help!!!!!! it's due this morning
zhuklara [117]

Answer:

Check the solution in both equations. The solution is ( − 1, 2). Solve the system by graphing: {− x + y = 12 x + y = 10 . Solve the system by graphing: {2x + y = 6 x + y = 1 . In all the systems of linear equations so far, the lines intersected and the solution was one point.

Hope it helps!!!

6 0
2 years ago
You purchase a car worth $25077 and make a down payment of $3560. You intend to repay the balance of the car with month end car
zubka84 [21]

Answer:

value of buyout is $4185.74

Step-by-step explanation:

given data

car worth = $25077

down payment = $3560

monthly payment = $336 = 336 × 6 = $2016 per semi annually

time = 5 year  = 10 half yearly

rate = 4.04 %

to find out

value of final buyout

solution

we know here loan amount will be 25077 - 3560 = $21517

and we find present value first by formula that is

present value = \frac{amount(1+r)^t - 1}{r (1+r)^t}

put here t = 10 and r = \frac{4.04}{200}

so

present value = \frac{2016(1+\frac{4.04}{200})^10 - 1}{r (1+\frac{4.04}{200})^10}

present value = 18089.96

so

loan unpaid amount is here

loan unpaid amount = 21517 - 18089.96

loan unpaid amount = $3427.04

so

now we calculate value of buyout

that is express as

amount = principal × (1+r)^{t}

amount = 3427.04 × (1+\frac{4.04}{200})^{10}

amount = 4185.74

so value of buyout is $4185.74

7 0
3 years ago
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