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3 years ago

Simplify your answer and write as in improper fraction or whole number. 9 divide 7/4

Mathematics

1 answer:

Setler79 [48]3 years ago

5 0

9 divided by 7/4=36/7=5 1/7.
So the answer is 5 1/7 the whole number.

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When a sunfloweris 2 weeks old it is 38 centimeters tall when it is 6 weeks old it is 114 cm tall how tall is it when it is 3 ½

Anna11 [10]

2 wk --- 38 cm
3.5 wk --- x cm
x = 3.5 wk x 38 cm
---------------------
2 wk
x= 66.5 cm

5 0

3 years ago

What is 3 In3-In9 expressed as a single natural logarithim

Alexandra [31]

$3 \ln 3 - \ln 9 = 3 \ln 3 - \ln 3 ^2 = 3 \ln 3 - 2 \ln 3 = \ln 3$

Answer: $\ln 3$

7 0

3 years ago

Read 2 more answers

Solve for x:

slava [35]

Answer:

Step-by-step explanation:

Any value of x makes the equation true.

4 0

3 years ago

Pls help me with this question and explain how you got the answer!!!!!

Luba_88 [7]

Answer:

-87

Step-by-step explanation:

So, first to find x you need to subtract 121 from 180. You do this because both the angle which measures 121 degrees and x lie on the same line, and since a line has an angle measure of 180, you do 180-121 to find x. The same thing can be done for y. Since the angle measure of 34 degrees and y lie on the same line you can calculate 180-34 to get y. So, let's do that.

180-121=x

59=x

180-34=y

146=y

Once you've done that you can easily subtract the two and get your answer.

x-y

substitute the answer for the variables and get

59-146

and then your answer is

-87

4 0

3 years ago

B. Determine the values of a and b so that f is continuous. Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$

So, the value of $a \ and \ b= \frac{1}{2}$

4 0

3 years ago