36 clowns and zebras..
if there are twice as many zebras as clowns then divide the amount by 2
36/2 = 18 so..
now there are 18 zebras and 18 clowns but we want twice as many zebras..

so by process of elimination we can figure out that
there are 24 zebras and 12 clowns which = 36
the answer is 24 zebras Connor counted

5 0

3 years ago

Question Help

stepladder [879]

Set R(x) equal to C(x). Solve the resulting equation for x, paying attention to the domain of C(x):

Solve 200x-2x^2 = -x^2 + 25x + 31000 for x greater than or equal to zero but less than or equal to x. That means you must reject any solution outside of this domain.

Rearrange all of these terms on the left side of your equation and place zero on the right side. Next, rearrange all of the terms on the left side in descending order by powers of x. Next, solve the resulting quadratic equation. Make certain to reject any x that does not fall within [0,100].

6 0

4 years ago

a candy necklace is extended from the top of a 10-foot ice cream cone to the ground. The necklace makes a 55 degree angle of the

Finger [1]

Answer:

The length of the necklace is 12.20 foot

Step-by-step explanation:

Given as :

The height of the ice cream cone to the ground = h = 10 foot

The angle make by the necklace of the ice cream cone = 55°

Let The length of the necklace = L foot

<u>Now, from figure </u>

Height = BC = h foot

The length of the necklace = L = AC

So, Sin angle = $\dfrac{\textrm perpendicular}{\textrm hypotenuse}$

Or, Sin 55° = $\dfrac{\textrm BC}{\textrm AC}$

Or, 0.8191 = $\dfrac{h}{L}$

Or, 0.8191 = $\dfrac{10 foot}{L}$

Or, L = $\dfrac{10 foot}{0.8191}$

∴ L = 12.20 foot

So, The length of necklace = L = 12.20 foot

Hence The length of the necklace is 12.20 foot Answer

5 0

3 years ago

A furniture store has set aside 800 square feet to display its sofas and chairs. Each sofa utilizes 50 sq. ft. and each chair ut

miskamm [114]

Answer:

a) 50S + 30C ≤ 800

b) 1) MAX = S + C

2) Max = 0.03S + 0.05C

3) Max = 6S + 5C

Step-by-step explanation:

Given:

Total space = 800 square feet

Each sofa = 50 square feet

Each chair = 30 square feet

At least 5 sofas and 5 chairs are to be displayed.

a) Write a mathematical model representing the store's constraints:

Let S denote number of sofas displayed and C denote number of chairs displayed.

The mathematical model will be:

50S + 30C ≤ 800

At least 5 sofas are to be dispayed: S ≥ 5

At least 5 chairs are to be displayed: C ≥ 5

1) Maximize the total pieces of furniture displayed:

S + C = MAX

2) Maximize the total expected number of daily sales:

MAX = 0.03S + 0.05C

3) Maximize the total expected daily profit:

Given:

Profit on sofas = $200

Profit on chairs = $100

Max Expected daily profit =

Max = (200S * 0.03) + (100C * 0.05)

<em>Max = 6S + 5C</em>

6 0

3 years ago