36 clowns and zebras..
if there are twice as many zebras as clowns then divide the amount by 2
36/2 = 18 so..
now there are 18 zebras and 18 clowns but we want twice as many zebras..
so by process of elimination we can figure out that
there are 24 zebras and 12 clowns which = 36
the answer is 24 zebras Connor counted
Set R(x) equal to C(x). Solve the resulting equation for x, paying attention to the domain of C(x):
Solve 200x-2x^2 = -x^2 + 25x + 31000 for x greater than or equal to zero but less than or equal to x. That means you must reject any solution outside of this domain.
Rearrange all of these terms on the left side of your equation and place zero on the right side. Next, rearrange all of the terms on the left side in descending order by powers of x. Next, solve the resulting quadratic equation. Make certain to reject any x that does not fall within [0,100].
Answer:
The length of the necklace is 12.20 foot
Step-by-step explanation:
Given as :
The height of the ice cream cone to the ground = h = 10 foot
The angle make by the necklace of the ice cream cone = 55°
Let The length of the necklace = L foot
<u>Now, from figure </u>
Height = BC = h foot
The length of the necklace = L = AC
So, Sin angle = 
Or, Sin 55° = 
Or, 0.8191 = 
Or, 0.8191 = 
Or, L = 
∴ L = 12.20 foot
So, The length of necklace = L = 12.20 foot
Hence The length of the necklace is 12.20 foot Answer
Answer:
a) 50S + 30C ≤ 800
b) 1) MAX = S + C
2) Max = 0.03S + 0.05C
3) Max = 6S + 5C
Step-by-step explanation:
Given:
Total space = 800 square feet
Each sofa = 50 square feet
Each chair = 30 square feet
At least 5 sofas and 5 chairs are to be displayed.
a) Write a mathematical model representing the store's constraints:
Let S denote number of sofas displayed and C denote number of chairs displayed.
The mathematical model will be:
50S + 30C ≤ 800
At least 5 sofas are to be dispayed: S ≥ 5
At least 5 chairs are to be displayed: C ≥ 5
b)
1) Maximize the total pieces of furniture displayed:
S + C = MAX
2) Maximize the total expected number of daily sales:
MAX = 0.03S + 0.05C
3) Maximize the total expected daily profit:
Given:
Profit on sofas = $200
Profit on chairs = $100
Max Expected daily profit =
Max = (200S * 0.03) + (100C * 0.05)
<em>Max = 6S + 5C</em>