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3 years ago

Of all 25 marbles in a bag, 3 of the marbles

Mathematics

2 answers:

lozanna [386]3 years ago

6 0

Answer:

12%

Step-by-step explanation:

There are 25 marbles in all.Taking white marbles to be 3.the probablility will be 3/25 and as percent=3/25×100=12%

Tom [10]3 years ago

4 0

Answer:

You have a 12% chance of pulling out a white marble

Step-by-step explanation:

Their is 25 marbles in the bag and you have 3 out of 25 chance of pulling out a white marble. 3/25=0.12 so you have a 12% chance of pulling out a white marble.

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1.5x - 3y = 6 (solve for y)

d1i1m1o1n [39]

Hello :
1.5x - 3y = 6
3y = 1.5x - 6
y = (1.5x - 6)/3

7 0

3 years ago

Please help me I need to turn in tomorrow please help me

Monica [59]

Answer:

Answer: A. 0.2

Step-by-step explanation:

Probability

The circle graph shows the distribution of the makeup of the Riverside Municipal Choir.

The total number of choir sections is: 8+10+10+12=40

To calculate the probability of a member chosen at random comes from the alto section, we use the formula:

$\displaystyle P=\frac{8}{40}$

Calculating:

P = 0.2

Answer: A. 0.2

7 0

3 years ago

Use the following regression results to answer the remaining questions. Y measures average hourly earnings AHE in U.S. dollars f

Ulleksa [173]

Answer:

Check the explanation

Step-by-step explanation:

Y = 11.5 + 4.5*X1 -2.5*X2 +0.7*X3+1.6*X4 -2.4*X5 -2.8*X6

FOR JANE

X1 =1 , X2 =1 , X3 =5 , X4 =0 ,X5=0, X6=1

SO,

Y =11.5+(4.5*1)-(2.5*1)+(0.7*5)+0+0-(2.8*1)

= 14.2

..........................

FOR Sophie

X1 =1 , X2 =1 , X3 =10 , X4 =1 ,X5=0, X6=0

so,

Y =11.5+(4.5*1)-(2.5*1)+(0.7*10)+ (1.6*1)+0+0

= 22.1

3 0

4 years ago

In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second

Molodets [167]

Given:

In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second.

To find:

The equation for the given situation if the sum of the numbers is 77.

Solution:

a. Let the first number in the set is x.

The second is 3 more than the first. So, the second number is $(x+3)$ .

The 3rd number is a square of the second. So, the third number is $(x+3)^2$ .

Therefore, the first, second and third numbers are $x,(x+3),(x+3)^2$ respectively.

b. The sum of the numbers is 77.

First number + Second number + Third number = 77

c. So, the equation in terms of x is:

$x+(x+3)+(x+3)^2=77$

Therefore, the required equation is $x+(x+3)+(x+3)^2=77$ .

d. On simplification, we get

$x+x+3+x^2+6x+9=77$ $[\because (a+b)^2=a^2+2ab+b^2]$

$x^2+(6x+x+x)+(3+9)=77$

$x^2+8x+12=77$

Subtract 77 from both sides.

$x^2+8x+12-77=77-77$

$x^2+8x-65=0$

Therefore, the simplified form of the required equation is $x^2+8x-65=0$ .

6 0

3 years ago

I don't understand this )):

True [87]

Maybe you should contact your teacher

3 0

4 years ago