A) x/y = 2/3
B) x + y = 105
Solving Equation A for y
A) y = 1.5x
Substituting A into B
B) x + 1.5x = 105
2.5x = 105
x = 42
y = 63
Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.
Answer:
Dale live 315 miles from the mountains
Step-by-step explanation:
Let y be the speed of Dale to the mountains
Time taken by Dale to the mountains=7 hrs
Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1
Time taken by Dale back home = 5hours
Since it speed increased by 18 miles per hour back home it speed = y+18
So distance traveled home =speed × time = (y+18)5 ...... eqn 2
Since distance cover is same in both the eqn 1 and eqn 2.
Eqn 1 = eqn 2
7y = (y+18)5
7y = 5y + 90
7y - 5y = 90 (collection like terms)
2y = 90
Y = 45
Substitute for y in eqn 1 to get distance away from mountain
= 7y eqn 1
= 7×45
= 315 miles.
∴ Dale leave 315 miles from the mountains
D. 12 inches
hope this helps
Answer:
Step-by-step explanation:
1 yard = 3 feet = 36 in
so 1 in = 1/36 yard, 1 ft = 1/3 yard.
The volume of the layer of the topsoil, is:
4 in * 28 ft * 14 ft = 4 *(1/36)*23*(1/3)*17*(1/3) yard cubed =
(4*28*14)/(36*3*3)= 1955/324=
The store only sells increments of 1/4 = 0.25 cubic yards.
we need 6.034/0.25=
So we need to buy 25 (24 will not be enough) increments of 1/4 cubic yards.
