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Mice21 [21]
3 years ago
15

Please feel me the algebraic expression of this. Added a picture!

Mathematics
1 answer:
Lina20 [59]3 years ago
8 0

Answer:

I think the answer is = a^3+5c Step-by-step explanation:

first put "a" to the 3rd power then increse it by 5 times c.

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2π/5

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Amrita thinks of a number. She doubles it, adds 9 , divides her answer by 3 and finally subtracts 1 . She obtains the same numbe
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Amrita's number is 6

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x               Double the unknown number

2x             Add 9

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3 years ago
Find the two smallest possible solutions to part 1a​
bixtya [17]
<h3>Answer: A. 5/12, 25/12</h3>

============================

Work Shown:

12*sin(2pi/5*x)+10 = 16

12*sin(2pi/5*x) = 16-10

12*sin(2pi/5*x) = 6

sin(2pi/5*x) = 6/12

sin(2pi/5*x) = 0.5

2pi/5*x = arcsin(0.5)

2pi/5*x = pi/6+2pi*n or 2pi/5*x = 5pi/6+2pi*n

2/5*x = 1/6+2*n or 2/5*x = 5/6+2*n

x = (5/2)*(1/6+2*n) or x = (5/2)*(5/6+2*n)

x = 5/12+5n or x = 25/12+5n

these equations form the set of all solutions. The n is any integer.

--------

The two smallest positive solutions occur when n = 0, so,

x = 5/12+5n or x = 25/12+5n

x = 5/12+5*0 or x = 25/12+5*0

x = 5/12 or x = 25/12

--------

Plugging either x value into the expression 12*sin(2pi/5*x)+10 should yield 16, which would confirm the two answers.

7 0
3 years ago
Read 2 more answers
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