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Yakvenalex [24]
3 years ago
13

What is the x-coordinate of the point that divides the directed line segment from K to J into a ratio of 1:3?

Mathematics
2 answers:
klasskru [66]3 years ago
8 0

Step 1

<u>Find the distance KJ in the x-coordinate</u>

we know that

the distance between two points with only one coordinate is equal to

d=\left|x_2-x_1\right|

substitute the values

d=\left|9-1\right|=8\ units

Step 2

<u>Find the x-coordinate of the point  that divides the directed line segment from K to J into a ratio of 1:3</u>

we know that

the ratio is 1:3

so

1+3=4

Divided the distance  KJ in the x-coordinate by 4

8/4=2\ units

Adds the x-coordinate of J to  3 times  2\ units

1+3*(2)=7\ units

therefore

<u>the answer is the option</u>

7\ units

ruslelena [56]3 years ago
4 0
Since we need a point that divides K-->J into two segments in a 1:3 ratio, let's flip it to a 3:1 ratio in the J-->K direction. That means that this point is 3/(3+1) = 3/4 of the way up line JK.
Let's take 3/4 of the x of K (plus the 1 for the x of J):
3/4×(9 - 1) + 1 (because the beginning ofvthe line, at J, has an x of 1)...
3/4×(8) + 1 = 6 + 1 = 7
Therefore the answer is C) 7
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<h2>○=> <u>Correct option</u> :</h2><h2>\color{plum}\tt\bold{(B)}</h2><h3>○=> <u>Steps to derive correct option</u> :</h3>

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