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Bumek [7]
3 years ago
14

PLEASE GEOMETRY HELP!! FIND THE LENGTH OF ARC PQR. EXPLAIN PLEASE!! BOGUS ANSWERS REPORTED

Mathematics
1 answer:
deff fn [24]3 years ago
8 0

First we need to find the measurement of arc PQ.

And sum of measurement of all arc angles is 360 degree.

Let measurement of arc PQ is x degree.

Therefore, we get

150+73+x+65=360
\\
288+x =360
\\
x =360-288=72

So measurement of arc PQ is 72.

And measurement of arc PQR is the sum of the measurement of arc PQ and QR.

That is

m \ PQR = 72 +65 = 137

measurement of Arc PQR = 137 degree= 2.39 radian

And radius is 6.48 inches

And arc length is the product of radius and central angle in radians .

That is

PQR= 6.48*2.39=15.5 inches

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Answer:

Perimeter of rectangle 1=4x+4

Perimeter of rectangle 2=4x+4

Step-by-step explanation:

Two squares with the same dimension

Square 1: let length=x

Square 2: let length=x

Since they have same dimensions

He added two inches to the length of square 1 to make it a rectangle

Rectangle 1: width=x, length=x+2

Perimeter=2(l+w)

=2{(x+2)+x}

=2(x+2+x)

=2(2x+2)

=4x+4

He added two inches to the width of square 2 to make it a rectangle

Rectangle 2: length=x, width=x+2

Perimeter=2(l+w)

=2{(x+(x+2)}

=2(x+x+2)

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The two rectangles have equal perimeter

3 0
3 years ago
A store plans to sell two different game consoles, the YuuMi and the ZBox. The store’s wholesale cost for a YuuMi is $250, and t
strojnjashka [21]

9514 1404 393

Answer:

  • Constraints: x + y ≤ 250; 250x +400y ≤ 70000; x ≥ 0; y ≥ 0
  • Objective formula: p = 45x +50y
  • 200 YuuMi and 50 ZBox should be stocked
  • maximum profit is $11,500

Step-by-step explanation:

Let x and y represent the numbers of YuuMi and ZBox consoles, respectively. The inventory cost must be at most 70,000, so that constraint is ...

  250x +400y ≤ 70000

The number sold will be at most 250 units, so that constraint is ...

  x + y ≤ 250

Additionally, we require x ≥ 0 and y ≥ 0.

__

A profit of 295-250 = 45 is made on each YuuMi, and a profit of 450-400 = 50 is made on each ZBox. So, if we want to maximize profit, our objective function is ...

  profit = 45x +50y

__

A graph is shown in the attachment. The vertex of the feasible region that maximizes profit is (x, y) = (200, 50).

200 YuuMi and 50 ZBox consoles should be stocked to maximize profit. The maximum monthly profit is $11,500.

4 0
3 years ago
A swimming pool is drained at the end of each summer. Fifteen gallons of water are removed per minute. How much does the amount
BartSMP [9]
Multiplying -15 by 60 yields -900, so the amount of water in the pool changes by -900 gallons in one hour.
7 0
3 years ago
find the probability of being delt 5 clubs and 3 cards with one of each remaining suit in 8 card poker
kumpel [21]

Answer: 0.003757(approx).

Step-by-step explanation:

Total number of combinations of selecting r things out of n things is given by:-

^nC_r=\dfrac{n!}{r!(n-r)!}

Total cards in a deck = 52

Total number of ways of choosing 8 cards out of 52 = ^{52}C_8

Total number of ways to choose 5 clubs and 3 cards with one of each remaining suit = ^{13}C_5\times^{13}C_1\times^{13}C_1\times^{13}C_1  [since 1 suit has 13 cards]

The required probability = =\dfrac{^{13}C_5\times^{13}C_1\times^{13}C_1\times^{13}C_1}{^{52}C_8}

=\dfrac{\dfrac{13!}{5!8!}\times13\times13\times13}{\dfrac{52!}{8!44!}}\\\\=\dfrac{24167}{6431950}\\\\\approx0.003757

Hence, the required probability is 0.003757 (approx).

5 0
3 years ago
Simplify each expression then factor the expression 14-28t-5(7+10t)
ludmilkaskok [199]

Answer:

Simplified: -21-98t

Factored: -7(14t+3)

Step-by-step explanation:

The given expresion is:

14-28t-5(7+10t)

We expand the parenthesis to get:

14 - 28t -35 - 70t

We group like terms to get:

14 -35  - 28t- 70t

We combine similar terms to get:

- 21- 98t

We now factor to obtain:

- 21- 98t =  - 7(14t + 3)

5 0
3 years ago
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