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elena-s [515]
4 years ago
6

Click for question !!!!!!!!

Mathematics
1 answer:
kotegsom [21]4 years ago
3 0
Divide both sides by 4pi, then take the square root of both sides. You will not get an actual value, but the answer should be
\sqrt{ \frac{a}{4\pi} }
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PLEASE SHOW FULL SOLUTIONS !!!!! WILL MARK BRAINLIEST FOR THE BEST ANSWER. THANK YOU AND GOD BLESS.
zhenek [66]

Answer:

a = 8

b ≠ 18

Step-by-step explanation:

y = 4x - 7

2y = ax + b

For there to be no solution, the lines (if graphed) should be parallel meaning that their slopes are equal but the y-intercepts are different

y = mx +b is the equation of a line where m is the slope and b is the y-intercept

Multiply the first equation by 2

2y = 8x - 14

2y = ax + b

So a has to equal 8

b can be anything except 14 (otherwise the lines would be the same)

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3 years ago
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Firdavs [7]

Answer:

Step-by-step explanation:

It’s c believe me

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A television Mark 1600 was sold for 1200 what percent discount was given on that television​
adoni [48]

Answer:

25%

Step-by-step explanation:

Discount = 1600 - 1200 = 400

Percentage discount

=  \frac{400}{1600}  \times 100 \\  \\  =  \frac{400}{16}  \\  \\  = 25\%

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3 years ago
Can anyone please help!!!
quester [9]

Answer:

Question 9

(a) The distance, Jalaj walks in one day is 4.4 km

(b) The amount Jalaj raises after walking for 22 km at the end of the 5 days is $8

Question 10

(b) The difference between the largest and smallest areas is 2,400 m²

Step-by-step explanation:

Question 9

(a) The distance Jalaj walks in 5 days = 22 km

Whereby Jalaj walks equal distance every day, we have;

The distance, Jalaj walks in one day = 22 km/5 days = 4.4 km/day

The distance, Jalaj walks in one day = 4.4 km

(b) The amount he raises for every kilometer he walks = $1.60

The amount he raises after walking for 22 km at the end of the 5 days = 5 × $1.60  = $8

Question 10

(b) The given side length of the square = 120 meters to the nearest 10 meters

Therefore;

The maximum dimension for the side length of the square = 120 + 10/2 = 125

The largest possible area of the square, A_l = 125 m × 125 m = 15,625 m²

The minimum dimension for the side length of the square = 120 m - 10 m/2 = 115 m

The smallest possible area of the square, A_s = 115 m × 115 m = 13,225 m².

The difference between the largest and smallest areas, A_l - A_s = 15,625 - 13,225 = 2,400 m².

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3 years ago
What is the value of the expression “two less than six times the difference of a number and five" when n =
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It’s 16 because Ik I did it before so do y worry
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