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3 years ago

6

Bill is building a model of a square pyramid for a class project. The side length of the square base is 10 inches and the slant

height of the pyramid is 15 inches. What is the surface area of the model pyramid?

2 answers:

Zolol [24]3 years ago

6 0

The surface area for the square pyramid is A= 416.23

k0ka [10]3 years ago

5 0

Answer:

400in.^2 < gradpoint

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3 years ago

The temperature in the morning was−8 °F. The temperature dropped 13 degrees by night. What is the temperature at night?

Firlakuza [10]

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3 years ago

Find the two small as possible solutions

solong [7]

Answer: $\bold{b)\quad \dfrac{5}{6},\ \dfrac{25}{6}}$

<u>Step-by-step explanation:</u>

$12cos\bigg(\dfrac{2\pi}{5}x\bigg)+10=16\\\\\\12cos\bigg(\dfrac{2\pi}{5}x\bigg)=6\\\\\\cos\bigg(\dfrac{2\pi}{5}x\bigg)=\dfrac{1}{2}\\\\\\cos^{-1}\bigg[cos\bigg(\dfrac{2\pi}{5}x\bigg)\bigg]=cos^{-1}\bigg(\dfrac{1}{2}\bigg)$

$\text{Use the Unit Circle to determine when}\ cos=\dfrac{1}{2}\quad \rightarrow \quad\text{at}\ \dfrac{\pi}{3}\ and \ \dfrac{5\pi}{3}\\\\\\\dfrac{2\pi}{5}x=\dfrac{\pi}{3}\qquad and\qquad \dfrac{2\pi}{5}x=\dfrac{5\pi}{3}\\\\\\\bigg(\dfrac{5}{2\pi}\bigg)\dfrac{2\pi}{5}x=\dfrac{\pi}{3}\bigg(\dfrac{5}{2\pi}\bigg)\quad and\quad \bigg(\dfrac{5}{2\pi}\bigg)\dfrac{2\pi}{5}x=\dfrac{5\pi}{3}\bigg(\dfrac{5}{2\pi}\bigg)\\\\\\.\qquad \qquad \large\boxed{x=\dfrac{5}{6}\qquad and \qquad x=\dfrac{25}{6}}$

6 0

3 years ago

Read 2 more answers

Convert the rectangular coordinates to polar coordinates with

NikAS [45]

Given:

Rectangular coordinate = (8, 6)

To convert:

Rectangular coordinate to polar coordinate with r > 0 and 0 ≤ θ < 2π.

Solution:

Let us find r:

$r=\sqrt{x^{2}+y^{2}}$

$r=\sqrt{8^{2}+6^{2}}$

$r=\sqrt{100}$

r = 10

Now, find θ:

$$\tan \theta=\frac{y}{x}$

$$\tan \theta=\frac{6}{8}$

Cancel the common factor 2.

$$\tan \theta=\frac{3}{4}$

$$\theta=\tan^{-1} \left(\frac{3}{4}\right)$

θ = 36.87°

The polar coordinates are (r, θ) = (10, 36.87°).

6 0

3 years ago