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ollegr [7]
3 years ago
11

Calculate and record the expected mass of benzoic acid required to react with 20.00 ml of a 0.100 m sodium hydroxide solution. r

ecord the mass of benzoic acid using three significant digits in your lab notes.

Chemistry
1 answer:
Marina CMI [18]3 years ago
5 0
Benzoic acid reacts with sodium hydroxide based on the equation shown in the attached picture.

It is clear that the ration between the benzoic acid and the sodium hydroxide is 1:1 in this reaction.

So, to answer this question, we will calculate the number of moles of sodium hydroxide used, equate it to the number of moles of benzoic acid and then calculate the mass of the calculated number of moles.

molarity = number of moles of solute / liter of solvent
0.1 = number of moles of sodium hydroxide / 0.02 liters
number of moles of sodium hydroxide = 0.002 moles

Therefore, number of moles of benzoic acid is also 0.002 moles
molar mass of benzoic acid = <span>122.12 grams

Therefore, the required mass of benzoic acid = 0.002 x </span><span>122.12
                                                                         = 0.2444 moles</span>

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yawa3891 [41]

Answer:

m_{O_2}=120gO_2

Explanation:

Hello!

In this case, since the decomposition of potassium chlorate is:

2KClO_3\rightarrow 2KCl+3O_2

We can see a 2:3 mole ratio between potassium chlorate and oxygen (molar mass 32.0 g/mol), thus, via stoichiometry, we compute the mass of oxygen that are produced by the decomposition of 2.50 moles of this reactant:

m_{O_2}=2.50molKClO_3*\frac{3molO_2}{2molKClO_3} *\frac{32.0gO_2}{1molO_2}\\\\m_{O_2}=120gO_2

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8 0
3 years ago
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This is an example of a physical change because the ice cubes began to melt.

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6 0
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Answer:

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6 0
3 years ago
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Get the answers to these questions

Back to the Unit 10 Old Tests Page

Back to the Unit 10 Page

Back to the Main Page

5 0
3 years ago
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