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ollegr [7]
3 years ago
11

Calculate and record the expected mass of benzoic acid required to react with 20.00 ml of a 0.100 m sodium hydroxide solution. r

ecord the mass of benzoic acid using three significant digits in your lab notes.

Chemistry
1 answer:
Marina CMI [18]3 years ago
5 0
Benzoic acid reacts with sodium hydroxide based on the equation shown in the attached picture.

It is clear that the ration between the benzoic acid and the sodium hydroxide is 1:1 in this reaction.

So, to answer this question, we will calculate the number of moles of sodium hydroxide used, equate it to the number of moles of benzoic acid and then calculate the mass of the calculated number of moles.

molarity = number of moles of solute / liter of solvent
0.1 = number of moles of sodium hydroxide / 0.02 liters
number of moles of sodium hydroxide = 0.002 moles

Therefore, number of moles of benzoic acid is also 0.002 moles
molar mass of benzoic acid = <span>122.12 grams

Therefore, the required mass of benzoic acid = 0.002 x </span><span>122.12
                                                                         = 0.2444 moles</span>

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234+34.1 add and round to 2 significant figures
marin [14]
Like this? 234+34.1= 268.1 then round. If it is less than 5 then you round down if it is more then you round up. Because it is less the final number would be 268.1=268
3 0
3 years ago
How many grams of ammonia (NH3) can be produced by the synthesis of excess hydrogen gas (H2) and 253.8 grams of nitrogen gas (N2
kogti [31]

Answer:

308.2 g of NH₃.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

3H₂ + N₂ —> 2NH₃

Next, we shall determine the mass of N₂ that reacted and the mass of NH₃ produced from the balanced equation. This can be obtained as follow:

Molar mass of N₂ = 2 × 14 = 28 g/mol

Mass of N₂ from the balanced equation = 1 × 28 = 28 g

Molar mass of NH₃ = 14 + (3×1)

= 14 + 3 = 17 g/mol

Mass of NH₃ from the balanced equation = 2 × 17 = 34 g

Summary:

From the balanced equation above,

28 g of N₂ reacted to produce 34 g of NH₃.

Finally, we shall determine the mass of NH₃ produced by the reaction of 253.8 g of N₂. This can be obtained as illustrated below:

From the balanced equation above,

28 g of N₂ reacted to produce 34 g of NH₃.

Therefore, 253.8 g of N₂ will react to produce = (253.8 × 34)/28 = 308.2 g of NH₃.

Thus, 308.2 g of NH₃ were obtained from the reaction.

8 0
2 years ago
Find the density of an object that has a mass of 28 grams and a volume of 2 points<br> 38.6 cm^3. *
Shtirlitz [24]

Answer:

<h2>0.73 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{28}{38.6}  \\  =0.72538...

We have the final answer as

<h3>0.73 g/cm³</h3>

Hope this helps you

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A. Carbon monoxide
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c.
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f.
8 0
3 years ago
Please help!!! I'll give brainliest to the most helpful answer
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87) A
88) D
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