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Georgia [21]
3 years ago
7

The Greeks were the first to use the term _____. atom electron neutron proton

Chemistry
2 answers:
kotegsom [21]3 years ago
6 0
I think the correct answer from the choices listed above is the first option. The Greeks were the first to use the term atom. In 450 BCE, Democritus coined the term átomos which means "uncuttable" or "the smallest indivisible particle of matter". 
kotegsom [21]3 years ago
3 0

Answer:

Atom

Explanation:

The Greeks first used the word "atomos" or atom.

There was a philosopher by the name of Leucippus of Miletus, and he had the idea that if you cut an object in half, and then in half again, and in half again, and so on... eventually you would get to a particle that cannot be cut in half (they were talking about the atom, however we now know that splitting an atom releases large amounts of radiation). The word atomos in Greek means "uncuttable".

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KatRina [158]

The formula for the change in Gibbs energy of a solid is:

ΔG = Vm ΔP

where, ΔG is change in Gibbs, Vm is molar volume, ΔP is change in pressure

ΔP = P(final) – P(initial)

P(final) = 1 atm = 101325 Pa

P(initial) = ρ_water *g *h = (1030 kg/m^3) * 9.8 m/s^2 * 2000 m = 20188000 kg m/s^2 = 20188000 Pa

Vm = (950 kg/m^3) * (1000 mol / 891.48 kg) = 1065.64 mol/m^3

 

So,

ΔG = (1065.64 mol/m^3) * (101325 Pa - 20188000 Pa)

<span>ΔG = -21405164347 J = -21.4 GJ</span>

8 0
3 years ago
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FrozenT [24]

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2 years ago
Two systems with heat capacities 19.9 J mol-1 K-1 and 28.2 ] mol 1 K-1 respectively interact thermally and come to an equilibriu
MAVERICK [17]

Answer : The initial temperature of system 2 is, 19.415^oC

Explanation :

In this problem we assumed that the total energy of the combined systems remains constant.

-q_1=q_2

m\times c_1\times (T_f-T_1)=-m\times c_2\times (T_f-T_2)

The mass remains same.

where,

C_1 = heat capacity of system 1 = 19.9 J/mole.K

C_2 = heat capacity of system 2 = 28.2 J/mole.K

T_f = final temperature of system = 30^oC=273+30=303K

T_1 = initial temperature of system 1 = 45^oC=273+45=318K

T_2 = initial temperature of system 2 = ?

Now put all the given values in the above formula, we get

-19.9J/mole.K\times (303-318)K=28.2J/mole.K\times (303-T_2)K

T_2=292.415K

T_2=292.415-273=19.415^oC

Therefore, the initial temperature of system 2 is, 19.415^oC

8 0
3 years ago
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