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Snowcat [4.5K]
2 years ago
13

Look back at parts A and B to compare the properties of the unknown elements with the properties of the known

Chemistry
1 answer:
valentina_108 [34]2 years ago
3 0
2 because it was a scam and
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CH4 (g) yields C(g) + 4H (g) (reaction for expansion)
anyanavicka [17]

Answer:

Here's what I find.

Explanation:

\rm CH$_{4}$(g) $\, \rightleftharpoons \,$ C(g) + 4H(g)

\text{Same} =\begin{cases}1. & \text{The number of atoms of each element}\\2. & \text{The state of the methane molecules}\\4. &\text{The state of the carbon atoms}\\\end{cases}

\text{Different} =\begin{cases}3. & \text{The enthalpy change of the reaction}\\\end{cases}

The sign of ΔH changes when you reverse the reaction.  

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2 years ago
In a gas grill, 29 lbs propane C3H8 are
dimulka [17.4K]

Answer : The mass of combustion products formed are 134 lbs.

Explanation :

The balanced chemical reaction will be:

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

Given :

Mass of C_3H_8 = 29 lbs = 13154.2 g

conversion used : 1 lbs = 453.592 g

Molar mass of C_3H_8 = 44 g/mole

First we have to calculate the moles of C_3H_8.

\text{ Moles of }C_3H_8=\frac{\text{ Mass of }C_3H_8}{\text{ Molar mass of }C_3H_8}=\frac{13154.2g}{44g/mole}=298.9moles

Now we have to calculate the moles of CO_2 and H_2O.

From the balanced chemical reaction we conclude that,

As, 1 mole of C_3H_8 react to give 3 moles of CO_2

So, 298.9 mole of C_3H_8 react to give 298.9\times 3=896.7 moles of CO_2

and,

As, 1 mole of C_3H_8 react to give 4 moles of H_2O

So, 298.9 mole of C_3H_8 react to give 298.9\times 4=1195.6 moles of H_2O

Now we have to calculate the mass of CO_2 and H_2O.

Molar mass of CO_2 = 44 g/mole

Molar mass of H_2O = 18 g/mole

\text{Mass of }CO_2=\text{Moles of }CO_2\times \text{Molar mass }CO_2

\text{Mass of }CO_2=896.7mole\times 44g/mole=39454.8g=86.98lbs

and,

\text{Mass of }H_2O=\text{Moles of }H_2O\times \text{Molar mass }H_2O

\text{Mass of }H_2O=1195.6mole\times 18g/mole=21520.8g=47.44lbs

The total mass of products = Mass of CO_2 + Mass of H_2O

The total mass of products = 86.98 + 47.44 = 134.42 ≈ 134 lbs

Therefore, the mass of combustion products formed are 134 lbs.

6 0
3 years ago
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