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3 years ago

the length of a rectangle is four less than three times the width. if the perimeter is 36, find the width.

Mathematics

1 answer:

nika2105 [10]3 years ago

5 0

Answer:

w = 5.5

Step-by-step explanation

8w-8=36

+8 +8

8w=44

/8 /8

w= 5.5

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The difference in 4,632 and 20,000 is what number

Oksanka [162]

15,368 Is The Answer

3 0

3 years ago

Find the leg of each isosceles right triangle when the hypotenuse is 5 square root 6

kozerog [31]

Hypotenuse = 5√6

Let the length of each leg be x, since it is Isosceles .

x² + x² = (5√6)²

2x² = (5 * 5 * √6 * √6)

2x² = 150

x² = 150/2

x² = 75

x = √75

x = √(25 * 3)

x = √25 * √3

x = 5√3

5 0

3 years ago

4t2–40t+84 factorise quadratics

Evgen [1.6K]

Answer:

4( t - 7) ( t - 3 )

Step-by-step explanation:

4t² - 40t + 84

4(t² - 10t + 21)

4( t - 7) ( t - 3 )

6 0

3 years ago

Read 2 more answers

(x-4)/5=9-(2x-41)/9

jok3333 [9.3K]

For this question, you have to take Least Common Multiplier for which in this case will be "45" as, the denominators can get similar and get multiplied by a same value to form a similar expression. This allows us to cancel out them by common factors. Full process shown below.

$\mathbf{Given \: \: Expression: \: \dfrac{x - 4}{5} = 9 - \dfrac{2x - 41}{9}}$

$\mathbf{\dfrac{x - 4}{5} \times 45 = 9 \times 45 - \dfrac{2x - 41}{9} \times 45}$

$\mathbf{9(x - 4) = 405 - 5 (2x - 41)}$

$\mathbf{9x - 36 = 405 - 10x + 205}$

$\mathbf{9x - 36 = - 10x + 610}$

$\mathbf{9x - 36 + 36 = - 10x + 610 + 36}$

$\mathbf{9x = - 10x + 646}$

$\mathbf{9x + 10x = - 10x + 646 + 10x}$

$\mathbf{19x = 646}$

$\mathbf{\dfrac{19x}{19} = \dfrac{646}{19}}$

$\mathbf{\therefore \quad x = 34}$

$\boxed{\mathbf{\underline{\therefore \quad Final \: \: Answer \: \: is; \: \: x = 34}}}$

Hope it helps.

3 0

3 years ago

Suppose a bank charges a base rate of $5 plus $0.10 per check for your checking account. You can switch to a different account t

wolverine [178]

Answer:

10 number of checks.

Cost = $6

Step-by-step explanation:

Given that:

Fixed Charges of first bank = $5

Charges of first bank per check = $0.10

Fixed Charges of second bank = $4

Charges of second bank per check = $0.20

To find:

Number of checks such that the charges for the banks become the same?

Solution:

Let the number of checks = $x$

Cost for the first bank for $x$ checks = $5 + $0.10 $x$

Cost for the second bank for $x$ checks = $4 + $0.20 $x$

As per question statement, both the costs are the same.

Comparing the values:

$5 + 0.10x = 4 + 0.20x\\\Rightarrow 0.10x = 1\\\Rightarrow x = 10$

So, for 10 number of checks the cost will be same.

The cost = 4 + 0.20 $\times$ 10 = <em>$6</em>

8 0

3 years ago