I just want to clarify how to find this, i havn't done this in a while.

Mathematics

1 answer:

Juliette [100K]3 years ago

5 0

You could either use a calculator on the internet or do it manually:

512
128 * 4
32 * 4 * 4
8 * 4 * 4 * 2 * 2
8 * 8 * 4 * 2

8 * 8 * 8 = 512

$\sqrt[3]{512} = 8$

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$\bf h=20ln(3t+2)+30\\\\
-------------------------------\\\\
\boxed{a}\\\\
\stackrel{0~years}{t=0}\qquad h=20ln[3(0)+2]+30\implies h=20ln(2)+30
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h\approx 43.86
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\boxed{b}\\\\
\stackrel{1~meter}{h=100}\qquad 100=20ln(3t+2)+30\implies 70=20ln(3t+2)
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$\bf \boxed{c}\\\\
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Read 2 more answers

Twice the product of 3and a number exceeds the sum of the number and 80 by 10.what is the number?

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First, create an equation with the criteria given.

If we let x be your number,
$2(3x) = 80 + x + 10$
( $2(3x)$ is twice the product of 3 and x, and if it exceeds $x+80$ by 10, then we add 10 to $x+80$ to make the two sides of the equation equal.)

Now, solve for $x$ .

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first term = 2 ...(given)

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