Point A is situated in the 4th quadrant. To obtain point B, we have to apply symmetry and reflect point A across the y-axis. Thus, the ordinate would still be -3, but the abscissa would be +2. So, point B is (+2,-3). For point C, we have to reflect it across the x-axis. This time, the abscissa remains to be -2, while the ordinate becomes +3. So, point C is (-2,+3).
Thus, the answer is <span>B(2, −3) and C(−2, 3)</span>
Answer:
(A)EF corresponds to E'F'
(C)∠EDG Is-congruent-to ∠E'D'G'
(D)∠DEF Is-congruent-to ∠D'E'F'
(F)The transformation is a rigid transformation.
Step-by-step explanation:
Given:
- Parallelogram DEFG is mapped to D'E'F'G'
- DEFG and D'E'F'G' have identical side lengths and angle measures.
The following applies:
- EF corresponds to E'F'
- ∠EDG Is-congruent-to ∠E'D'G'
- ∠DEF Is-congruent-to ∠D'E'F'
Now, a rigid transformation is a transformation of the plane that preserves length. Since the two parallelograms have identical side lengths:
- The transformation is a rigid transformation.
Note that a reflection is an isometric transformation. Therefore the statement "The transformation is not isometric" is INCORRECT.
FG and GD are adjacent sides, therefore they may not necessarily be congruent. Thus FG does not corresponds to G'D'
Answer:
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Step-by-step explanation:
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The area of the entire sector is 
The area of the triangle OAB is 
.
So, the area of the segment is 
