3 years ago

What is the solution to this system of linear equations: y-x=4 and y+2x=1

1 answer:

5 0

-x + y = 4
2x + y = 1
 -3x = 3
 -3 -3
 x = -1
 -x + y = 4
-(-1) + y = 4
 1 + y = 4
 - 1 - 1
 y = 3
(x, y) = (-1, 3)

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Margaret [11]

Answer:

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Step-by-step explanation:

Given

$V = 36x&^6y^8$

$L = 4x^3y^5$

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Required

Find the height of the prism

Volume (V) is calculated as:

$V =LWH$

Substitute values for V, L and W

$36x^6y^8 =4x^3y^5 * 3xy^2 * H$

Make H the subject

$H = \frac{36x^6y^8}{4x^3y^5 * 3xy^2}$

$H = \frac{36x^6y^8}{4*3x^3*x*y^5y^2}$

$H = \frac{36x^6y^8}{12x^4*y^7}$

Divide:

$H = 3x^{6-4}y^{8-7}$

$H = 3x^2y$

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