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Irina18 [472]
2 years ago
13

Joe needs to push his car 20 feet up a hill. If

Mathematics
1 answer:
Sever21 [200]2 years ago
5 0

Answer:

What if you have to push a heavy object up a ramp? Say, for example, you have to move a refrigerator. You want to go camping, and because you expect to catch plenty of fish, you decide to take your 100-kilogram refrigerator with you. The only catch is getting the refrigerator into your vehicle (see the figure). The refrigerator has to go up a 30-degree ramp that happens to have a static coefficient of friction with the refrigerator of 0.20 and a kinetic coefficient of friction of 0.15. The good news is that you have two friends to help you move the fridge. The bad news is that you can supply only 350 newtons of force each, so your friends panic.

The minimum force needed to push that refrigerator up the ramp has a magnitude Fpush, and it has to counter the component of the weight of the refrigerator acting along the ramp and the force due to friction.

The first step in this problem is to resolve the weight of the refrigerator into components parallel and perpendicular to the ramp. Take a look at the figure, which shows the refrigerator and the forces acting on it. The component of the weight of the refrigerator along the ramp is

Step-by-step explanation:

please rate thank and follow

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To make a triangle the angles have to add up to 180 degrees so 90+45+35=170 degrees not 180.

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Help me please it’s due today
Zolol [24]

Answer:

49 ft  

Step-by-step explanation:

h(t) = 56t - 16t²

This is the equation of a parabola.

We must solve the equation to find the time (t) when the ball reaches its maximum height (h).  

The coefficient of t² is negative, so the parabola opens downward, and the vertex is a maximum.

One way to solve this problem is to convert the equation to the vertex form.

We do that by completing the square.

Calculation:

h = -16t² + 56t  

Divide both sides by -16 to make the coefficient of  t² equal to 1.

(-1/16)h = t² - ⁷/₂t

Square half the coefficient of t

(-7/4)² = 49/16

Add and subtract it on the right-hand side

(-1/16)h = t² - ⁷/₂t  + 49/16 - 49/16  

Write the first three terms as the square of a binomial

(-1/16)h = (t - ⁷/₄)² - 49/16

Multiply both sides by -16

h = -16(t - ⁷/₄)² + 49

You have converted your equation to  the vertex form of a parabola:

y = a(t - h)² + k = 0,

where (h, k) is the vertex.

h = ⁷/₄ and k = 49, so the vertex is at (⁷/₄, 49).

The time to reach maximum height is ⁷/₄ s = 1.75 s.

The graph below shows that the ball reaches a maximum height of 49 ft after 1.75 s.

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2 years ago
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